anonymous
  • anonymous
What are the characteristics of a radical equation? How is solving radical equations similar to solving linear equations? Why is it important to check the solutions to a radical equation? Create your own radical equation. Describe in complete sentences and demonstrate the process in finding its solution(s) I'm clueless when it comes to this stuff, could anyone help me?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mertsj
  • Mertsj
The characteristics of a radical equation: 1. It contains a radical 2. It is solved by raising both sides of the equation to the appropriate power. 3. If the root is an even root, the radicand cannot be negative. It is important to check the solution because sometimes an extraneous root is introduced during the process of raising both sides to a power. 3. \[\sqrt{x+3}=2\] Since this is a second root, I will raise both sides to the second power. \[(\sqrt{x+3})^2=2^2\] Since raising to the second power is the inverse of extracting the second root, the equation becomes: \[x+3=4\] Now complete the solution by subtracting 3 from both sides. The result is: \[x=1\] Now the solution must be checked by replacing x with 1 in the original equation: \[\sqrt{1+3}=2\] Since the principal square root of 4 is indeed 2, the answer checks and the solution is x = 1
anonymous
  • anonymous
thanks so much, i know this was probably simple to you but its like greek for me, thanks again!!
Mertsj
  • Mertsj
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.