King
Balance the charges and masses in foll. equation:
I shall post equations in reply
Pls help wid explanantion !!
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King
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\[CuS + NO _{3}^{-} --> Cu ^{2+}+ \S _{8}+NO\]
King
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sry thats S8 in the product side
heena
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re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it
King
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no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction
heena
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hey is thiss redox reaction? right in which medium u have to do balancing?
heena
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i mean acidic medium or basic medium u are provided this info?
King
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acidic medium
heena
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ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u
King
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i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e- and i am not sure if Nitrogen loses 1 e- or gains 5 e- bcuz N oxidation state is +5 in reactant side
heena
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u know
NO3- here it charge is +5 and in product ide NO its charge is -2
means from being +5 to -2 is reduction right means its half reduction reaction
King
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in NO charge is 0
King
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haan mujhe hindi pata he
King
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u der?
heena
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rry actauly O have -2 charge always wid it ok its not evrytime gonna shown u
King
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oh ok!
King
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wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2
King
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and in NO N charge is +2 not -2 so its oxidation
heena
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ok now see
half reduction reaction half oxidation reaction
NO3- -------------> NO CuS----------------S8
+5 ---------------> +2 -2--------->0 [charge]
heena
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get this much ?
King
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ok i got it!thnk!
heena
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now we will balance
NO3- -------------> NO
H+ + NO3 -----------> NO + H2O
( by adding water balance this equation)
King
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ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong
King
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i got the 1st one
King
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\[Cr _{2}O _{7^{2-}}+I ^{-} -->Cr ^{3+}+I _{2}\]
King
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i multiply I by 2 in reactant side,and Cr by 2 in product side first
heena
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first u say den i ll solve
King
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then i find that Cr undergoes reduction by gaining 3 e- as it is +6->+3
and I undergoes oxidation by losing 2 e- +2->0
King
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so i cross multiply and get 28H+ + 2Cr2O7- + 6I- --->4Cr3+ +3I2 + 14H20
King
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but charges are not balanced so what to do?
King
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@heena u der?
heena
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give me a sec
King
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kk
heena
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srry wait
heena
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i m gettin
14H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 15e-
King
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if u put 7/2 H20 then masses are not balanced
King
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and in ure equation charges are not balanced
heena
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wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so
King
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no but my sir wants masses and chrges both balanced
heena
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iabove eqn is wrong
7H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 8e-
+5 -5
the only prob is sigm is different in charge :(
Callisto
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Hello :)
heena
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ok u done this with ion electron method
Callisto
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Eh... It's based on change in oxidation number..
heena
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but the way d way i m doing here wats troubling here @callistion can u guide?
Callisto
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+6, -1, +3, 0 are oxidation numbers.. and one marked with pencil is the change
heena
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yea i get that thing wat u done but i m thig wat i have done wrong here (:
Callisto
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gimme some time to write , please?
heena
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anyway i ll do dis qn later hope callisto will guide u in above problem @king bye
King
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@heena bye@callisto thnx a lot and bye!
Callisto
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People are leaving.. :(
Callisto
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Do you understand...?
heena
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y u upsad ?
dont worry i m still here :)
Callisto
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Good :) Do you understand?
heena
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yes mam :)
Callisto
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Great! and my mission's completed?
heena
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:) are u good in bio i need help?
Callisto
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i don't study Biology, sorry :(
heena
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no prob :) u knw hydrocarbon?