King
  • King
Balance the charges and masses in foll. equation: I shall post equations in reply Pls help wid explanantion !!
Chemistry
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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King
  • King
\[CuS + NO _{3}^{-} --> Cu ^{2+}+ \S _{8}+NO\]
King
  • King
sry thats S8 in the product side
anonymous
  • anonymous
re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it

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King
  • King
no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction
anonymous
  • anonymous
hey is thiss redox reaction? right in which medium u have to do balancing?
anonymous
  • anonymous
i mean acidic medium or basic medium u are provided this info?
King
  • King
acidic medium
anonymous
  • anonymous
ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u
King
  • King
i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e- and i am not sure if Nitrogen loses 1 e- or gains 5 e- bcuz N oxidation state is +5 in reactant side
anonymous
  • anonymous
u know NO3- here it charge is +5 and in product ide NO its charge is -2 means from being +5 to -2 is reduction right means its half reduction reaction
King
  • King
in NO charge is 0
King
  • King
haan mujhe hindi pata he
King
  • King
u der?
anonymous
  • anonymous
rry actauly O have -2 charge always wid it ok its not evrytime gonna shown u
King
  • King
oh ok!
King
  • King
wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2
King
  • King
and in NO N charge is +2 not -2 so its oxidation
anonymous
  • anonymous
ok now see half reduction reaction half oxidation reaction NO3- -------------> NO CuS----------------S8 +5 ---------------> +2 -2--------->0 [charge]
anonymous
  • anonymous
get this much ?
King
  • King
ok i got it!thnk!
anonymous
  • anonymous
now we will balance NO3- -------------> NO H+ + NO3 -----------> NO + H2O ( by adding water balance this equation)
King
  • King
ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong
King
  • King
i got the 1st one
King
  • King
\[Cr _{2}O _{7^{2-}}+I ^{-} -->Cr ^{3+}+I _{2}\]
King
  • King
i multiply I by 2 in reactant side,and Cr by 2 in product side first
anonymous
  • anonymous
first u say den i ll solve
King
  • King
then i find that Cr undergoes reduction by gaining 3 e- as it is +6->+3 and I undergoes oxidation by losing 2 e- +2->0
King
  • King
so i cross multiply and get 28H+ + 2Cr2O7- + 6I- --->4Cr3+ +3I2 + 14H20
King
  • King
but charges are not balanced so what to do?
King
  • King
@heena u der?
anonymous
  • anonymous
give me a sec
King
  • King
kk
anonymous
  • anonymous
srry wait
anonymous
  • anonymous
i m gettin 14H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 15e-
King
  • King
if u put 7/2 H20 then masses are not balanced
King
  • King
and in ure equation charges are not balanced
anonymous
  • anonymous
wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so
King
  • King
no but my sir wants masses and chrges both balanced
anonymous
  • anonymous
iabove eqn is wrong 7H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 8e- +5 -5 the only prob is sigm is different in charge :(
Callisto
  • Callisto
Hello :)
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anonymous
  • anonymous
ok u done this with ion electron method
Callisto
  • Callisto
Eh... It's based on change in oxidation number..
anonymous
  • anonymous
but the way d way i m doing here wats troubling here @callistion can u guide?
Callisto
  • Callisto
+6, -1, +3, 0 are oxidation numbers.. and one marked with pencil is the change
anonymous
  • anonymous
yea i get that thing wat u done but i m thig wat i have done wrong here (:
Callisto
  • Callisto
gimme some time to write , please?
anonymous
  • anonymous
anyway i ll do dis qn later hope callisto will guide u in above problem @king bye
King
  • King
@heena bye@callisto thnx a lot and bye!
Callisto
  • Callisto
People are leaving.. :(
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Callisto
  • Callisto
Do you understand...?
anonymous
  • anonymous
y u upsad ? dont worry i m still here :)
Callisto
  • Callisto
Good :) Do you understand?
anonymous
  • anonymous
yes mam :)
Callisto
  • Callisto
Great! and my mission's completed?
anonymous
  • anonymous
:) are u good in bio i need help?
Callisto
  • Callisto
i don't study Biology, sorry :(
anonymous
  • anonymous
no prob :) u knw hydrocarbon?

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