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King

  • 4 years ago

Balance the charges and masses in foll. equation: I shall post equations in reply Pls help wid explanantion !!

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  1. King
    • 4 years ago
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    \[CuS + NO _{3}^{-} --> Cu ^{2+}+ \S _{8}+NO\]

  2. King
    • 4 years ago
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    sry thats S8 in the product side

  3. heena
    • 4 years ago
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    re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it

  4. King
    • 4 years ago
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    no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction

  5. heena
    • 4 years ago
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    hey is thiss redox reaction? right in which medium u have to do balancing?

  6. heena
    • 4 years ago
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    i mean acidic medium or basic medium u are provided this info?

  7. King
    • 4 years ago
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    acidic medium

  8. heena
    • 4 years ago
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    ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u

  9. King
    • 4 years ago
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    i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e- and i am not sure if Nitrogen loses 1 e- or gains 5 e- bcuz N oxidation state is +5 in reactant side

  10. heena
    • 4 years ago
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    u know NO3- here it charge is +5 and in product ide NO its charge is -2 means from being +5 to -2 is reduction right means its half reduction reaction

  11. King
    • 4 years ago
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    in NO charge is 0

  12. King
    • 4 years ago
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    haan mujhe hindi pata he

  13. King
    • 4 years ago
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    u der?

  14. heena
    • 4 years ago
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    rry actauly O have -2 charge always wid it ok its not evrytime gonna shown u

  15. King
    • 4 years ago
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    oh ok!

  16. King
    • 4 years ago
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    wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2

  17. King
    • 4 years ago
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    and in NO N charge is +2 not -2 so its oxidation

  18. heena
    • 4 years ago
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    ok now see half reduction reaction half oxidation reaction NO3- -------------> NO CuS----------------S8 +5 ---------------> +2 -2--------->0 [charge]

  19. heena
    • 4 years ago
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    get this much ?

  20. King
    • 4 years ago
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    ok i got it!thnk!

  21. heena
    • 4 years ago
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    now we will balance NO3- -------------> NO H+ + NO3 -----------> NO + H2O ( by adding water balance this equation)

  22. King
    • 4 years ago
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    ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong

  23. King
    • 4 years ago
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    i got the 1st one

  24. King
    • 4 years ago
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    \[Cr _{2}O _{7^{2-}}+I ^{-} -->Cr ^{3+}+I _{2}\]

  25. King
    • 4 years ago
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    i multiply I by 2 in reactant side,and Cr by 2 in product side first

  26. heena
    • 4 years ago
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    first u say den i ll solve

  27. King
    • 4 years ago
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    then i find that Cr undergoes reduction by gaining 3 e- as it is +6->+3 and I undergoes oxidation by losing 2 e- +2->0

  28. King
    • 4 years ago
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    so i cross multiply and get 28H+ + 2Cr2O7- + 6I- --->4Cr3+ +3I2 + 14H20

  29. King
    • 4 years ago
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    but charges are not balanced so what to do?

  30. King
    • 4 years ago
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    @heena u der?

  31. heena
    • 4 years ago
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    give me a sec

  32. King
    • 4 years ago
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    kk

  33. heena
    • 4 years ago
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    srry wait

  34. heena
    • 4 years ago
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    i m gettin 14H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 15e-

  35. King
    • 4 years ago
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    if u put 7/2 H20 then masses are not balanced

  36. King
    • 4 years ago
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    and in ure equation charges are not balanced

  37. heena
    • 4 years ago
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    wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so

  38. King
    • 4 years ago
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    no but my sir wants masses and chrges both balanced

  39. heena
    • 4 years ago
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    iabove eqn is wrong 7H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 8e- +5 -5 the only prob is sigm is different in charge :(

  40. Callisto
    • 4 years ago
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    Hello :)

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  41. heena
    • 4 years ago
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    ok u done this with ion electron method

  42. Callisto
    • 4 years ago
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    Eh... It's based on change in oxidation number..

  43. heena
    • 4 years ago
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    but the way d way i m doing here wats troubling here @callistion can u guide?

  44. Callisto
    • 4 years ago
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    +6, -1, +3, 0 are oxidation numbers.. and one marked with pencil is the change

  45. heena
    • 4 years ago
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    yea i get that thing wat u done but i m thig wat i have done wrong here (:

  46. Callisto
    • 4 years ago
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    gimme some time to write , please?

  47. heena
    • 4 years ago
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    anyway i ll do dis qn later hope callisto will guide u in above problem @king bye

  48. King
    • 4 years ago
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    @heena bye@callisto thnx a lot and bye!

  49. Callisto
    • 4 years ago
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    People are leaving.. :(

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  50. Callisto
    • 4 years ago
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    Do you understand...?

  51. heena
    • 4 years ago
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    y u upsad ? dont worry i m still here :)

  52. Callisto
    • 4 years ago
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    Good :) Do you understand?

  53. heena
    • 4 years ago
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    yes mam :)

  54. Callisto
    • 4 years ago
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    Great! and my mission's completed?

  55. heena
    • 4 years ago
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    :) are u good in bio i need help?

  56. Callisto
    • 4 years ago
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    i don't study Biology, sorry :(

  57. heena
    • 4 years ago
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    no prob :) u knw hydrocarbon?

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