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King
 4 years ago
Balance the charges and masses in foll. equation:
I shall post equations in reply
Pls help wid explanantion !!
King
 4 years ago
Balance the charges and masses in foll. equation: I shall post equations in reply Pls help wid explanantion !!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[CuS + NO _{3}^{} > Cu ^{2+}+ \S _{8}+NO\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sry thats S8 in the product side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey is thiss redox reaction? right in which medium u have to do balancing?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mean acidic medium or basic medium u are provided this info?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e and i am not sure if Nitrogen loses 1 e or gains 5 e bcuz N oxidation state is +5 in reactant side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u know NO3 here it charge is +5 and in product ide NO its charge is 2 means from being +5 to 2 is reduction right means its half reduction reaction

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haan mujhe hindi pata he

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rry actauly O have 2 charge always wid it ok its not evrytime gonna shown u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and in NO N charge is +2 not 2 so its oxidation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok now see half reduction reaction half oxidation reaction NO3 > NO CuSS8 +5 > +2 2>0 [charge]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now we will balance NO3 > NO H+ + NO3 > NO + H2O ( by adding water balance this equation)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[Cr _{2}O _{7^{2}}+I ^{} >Cr ^{3+}+I _{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i multiply I by 2 in reactant side,and Cr by 2 in product side first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first u say den i ll solve

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then i find that Cr undergoes reduction by gaining 3 e as it is +6>+3 and I undergoes oxidation by losing 2 e +2>0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i cross multiply and get 28H+ + 2Cr2O7 + 6I >4Cr3+ +3I2 + 14H20

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but charges are not balanced so what to do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i m gettin 14H+ + cr2o72> 2Cr3+ + 7/2H2O + 15e

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u put 7/2 H20 then masses are not balanced

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and in ure equation charges are not balanced

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no but my sir wants masses and chrges both balanced

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0iabove eqn is wrong 7H+ + cr2o72> 2Cr3+ + 7/2H2O + 8e +5 5 the only prob is sigm is different in charge :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok u done this with ion electron method

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2Eh... It's based on change in oxidation number..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but the way d way i m doing here wats troubling here @callistion can u guide?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2+6, 1, +3, 0 are oxidation numbers.. and one marked with pencil is the change

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea i get that thing wat u done but i m thig wat i have done wrong here (:

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2gimme some time to write , please?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0anyway i ll do dis qn later hope callisto will guide u in above problem @king bye

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@heena bye@callisto thnx a lot and bye!

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2People are leaving.. :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y u upsad ? dont worry i m still here :)

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2Good :) Do you understand?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2Great! and my mission's completed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:) are u good in bio i need help?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.2i don't study Biology, sorry :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no prob :) u knw hydrocarbon?
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