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King

Balance the charges and masses in foll. equation: I shall post equations in reply Pls help wid explanantion !!

  • 2 years ago
  • 2 years ago

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  1. King
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    \[CuS + NO _{3}^{-} --> Cu ^{2+}+ \S _{8}+NO\]

    • 2 years ago
  2. King
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    sry thats S8 in the product side

    • 2 years ago
  3. heena
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    re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it

    • 2 years ago
  4. King
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    no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction

    • 2 years ago
  5. heena
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    hey is thiss redox reaction? right in which medium u have to do balancing?

    • 2 years ago
  6. heena
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    i mean acidic medium or basic medium u are provided this info?

    • 2 years ago
  7. King
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    acidic medium

    • 2 years ago
  8. heena
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    ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u

    • 2 years ago
  9. King
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    i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e- and i am not sure if Nitrogen loses 1 e- or gains 5 e- bcuz N oxidation state is +5 in reactant side

    • 2 years ago
  10. heena
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    u know NO3- here it charge is +5 and in product ide NO its charge is -2 means from being +5 to -2 is reduction right means its half reduction reaction

    • 2 years ago
  11. King
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    in NO charge is 0

    • 2 years ago
  12. King
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    haan mujhe hindi pata he

    • 2 years ago
  13. King
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    u der?

    • 2 years ago
  14. heena
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    rry actauly O have -2 charge always wid it ok its not evrytime gonna shown u

    • 2 years ago
  15. King
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    oh ok!

    • 2 years ago
  16. King
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    wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2

    • 2 years ago
  17. King
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    and in NO N charge is +2 not -2 so its oxidation

    • 2 years ago
  18. heena
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    ok now see half reduction reaction half oxidation reaction NO3- -------------> NO CuS----------------S8 +5 ---------------> +2 -2--------->0 [charge]

    • 2 years ago
  19. heena
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    get this much ?

    • 2 years ago
  20. King
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    ok i got it!thnk!

    • 2 years ago
  21. heena
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    now we will balance NO3- -------------> NO H+ + NO3 -----------> NO + H2O ( by adding water balance this equation)

    • 2 years ago
  22. King
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    ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong

    • 2 years ago
  23. King
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    i got the 1st one

    • 2 years ago
  24. King
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    \[Cr _{2}O _{7^{2-}}+I ^{-} -->Cr ^{3+}+I _{2}\]

    • 2 years ago
  25. King
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    i multiply I by 2 in reactant side,and Cr by 2 in product side first

    • 2 years ago
  26. heena
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    first u say den i ll solve

    • 2 years ago
  27. King
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    then i find that Cr undergoes reduction by gaining 3 e- as it is +6->+3 and I undergoes oxidation by losing 2 e- +2->0

    • 2 years ago
  28. King
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    so i cross multiply and get 28H+ + 2Cr2O7- + 6I- --->4Cr3+ +3I2 + 14H20

    • 2 years ago
  29. King
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    but charges are not balanced so what to do?

    • 2 years ago
  30. King
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    @heena u der?

    • 2 years ago
  31. heena
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    give me a sec

    • 2 years ago
  32. King
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    kk

    • 2 years ago
  33. heena
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    srry wait

    • 2 years ago
  34. heena
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    i m gettin 14H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 15e-

    • 2 years ago
  35. King
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    if u put 7/2 H20 then masses are not balanced

    • 2 years ago
  36. King
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    and in ure equation charges are not balanced

    • 2 years ago
  37. heena
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    wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so

    • 2 years ago
  38. King
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    no but my sir wants masses and chrges both balanced

    • 2 years ago
  39. heena
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    iabove eqn is wrong 7H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 8e- +5 -5 the only prob is sigm is different in charge :(

    • 2 years ago
  40. Callisto
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    Hello :)

    • 2 years ago
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  41. heena
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    ok u done this with ion electron method

    • 2 years ago
  42. Callisto
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    Eh... It's based on change in oxidation number..

    • 2 years ago
  43. heena
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    but the way d way i m doing here wats troubling here @callistion can u guide?

    • 2 years ago
  44. Callisto
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    +6, -1, +3, 0 are oxidation numbers.. and one marked with pencil is the change

    • 2 years ago
  45. heena
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    yea i get that thing wat u done but i m thig wat i have done wrong here (:

    • 2 years ago
  46. Callisto
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    gimme some time to write , please?

    • 2 years ago
  47. heena
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    anyway i ll do dis qn later hope callisto will guide u in above problem @king bye

    • 2 years ago
  48. King
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    @heena bye@callisto thnx a lot and bye!

    • 2 years ago
  49. Callisto
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    People are leaving.. :(

    • 2 years ago
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  50. Callisto
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    Do you understand...?

    • 2 years ago
  51. heena
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    y u upsad ? dont worry i m still here :)

    • 2 years ago
  52. Callisto
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    Good :) Do you understand?

    • 2 years ago
  53. heena
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    yes mam :)

    • 2 years ago
  54. Callisto
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    Great! and my mission's completed?

    • 2 years ago
  55. heena
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    :) are u good in bio i need help?

    • 2 years ago
  56. Callisto
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    i don't study Biology, sorry :(

    • 2 years ago
  57. heena
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    no prob :) u knw hydrocarbon?

    • 2 years ago
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