Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

King

  • 2 years ago

Balance the charges and masses in foll. equation: I shall post equations in reply Pls help wid explanantion !!

  • This Question is Closed
  1. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[CuS + NO _{3}^{-} --> Cu ^{2+}+ \S _{8}+NO\]

  2. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sry thats S8 in the product side

  3. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    re u sure equation i correct as if u see in the reaction O is not balanced first try to balance it

  4. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no my sir said that fr O we should balance using H20 and then add H+ ion to reactant side to balance H...oh yeah this is a acid base reaction

  5. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hey is thiss redox reaction? right in which medium u have to do balancing?

  6. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i mean acidic medium or basic medium u are provided this info?

  7. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    acidic medium

  8. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so first write down half oxidation and half reduction reaction if u are having problem in this step say ok i ll help u

  9. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont understand hw to do this prob.if u could explain i could try the remaining..as fr the prob i know that Copper loses 2 e- and i am not sure if Nitrogen loses 1 e- or gains 5 e- bcuz N oxidation state is +5 in reactant side

  10. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u know NO3- here it charge is +5 and in product ide NO its charge is -2 means from being +5 to -2 is reduction right means its half reduction reaction

  11. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in NO charge is 0

  12. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haan mujhe hindi pata he

  13. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u der?

  14. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    rry actauly O have -2 charge always wid it ok its not evrytime gonna shown u

  15. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok!

  16. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wat abt remaining can u do this 1 fr me wid steps so i can apply and do fr my other 2

  17. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and in NO N charge is +2 not -2 so its oxidation

  18. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok now see half reduction reaction half oxidation reaction NO3- -------------> NO CuS----------------S8 +5 ---------------> +2 -2--------->0 [charge]

  19. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    get this much ?

  20. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok i got it!thnk!

  21. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now we will balance NO3- -------------> NO H+ + NO3 -----------> NO + H2O ( by adding water balance this equation)

  22. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok luk at this prob i noted down oxidation and reduction reactions but still its coming wrong

  23. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got the 1st one

  24. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[Cr _{2}O _{7^{2-}}+I ^{-} -->Cr ^{3+}+I _{2}\]

  25. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i multiply I by 2 in reactant side,and Cr by 2 in product side first

  26. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    first u say den i ll solve

  27. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then i find that Cr undergoes reduction by gaining 3 e- as it is +6->+3 and I undergoes oxidation by losing 2 e- +2->0

  28. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so i cross multiply and get 28H+ + 2Cr2O7- + 6I- --->4Cr3+ +3I2 + 14H20

  29. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but charges are not balanced so what to do?

  30. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @heena u der?

  31. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    give me a sec

  32. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    kk

  33. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    srry wait

  34. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i m gettin 14H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 15e-

  35. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if u put 7/2 H20 then masses are not balanced

  36. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and in ure equation charges are not balanced

  37. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wen u do blcing in equtaion masses dont make any effect ok only mole volume dey do so

  38. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no but my sir wants masses and chrges both balanced

  39. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    iabove eqn is wrong 7H+ + cr2o7-2----------------> 2Cr3+ + 7/2H2O + 8e- +5 -5 the only prob is sigm is different in charge :(

  40. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Hello :)

    1 Attachment
  41. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok u done this with ion electron method

  42. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Eh... It's based on change in oxidation number..

  43. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but the way d way i m doing here wats troubling here @callistion can u guide?

  44. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    +6, -1, +3, 0 are oxidation numbers.. and one marked with pencil is the change

  45. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea i get that thing wat u done but i m thig wat i have done wrong here (:

  46. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    gimme some time to write , please?

  47. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    anyway i ll do dis qn later hope callisto will guide u in above problem @king bye

  48. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @heena bye@callisto thnx a lot and bye!

  49. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    People are leaving.. :(

    1 Attachment
  50. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Do you understand...?

  51. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y u upsad ? dont worry i m still here :)

  52. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Good :) Do you understand?

  53. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes mam :)

  54. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Great! and my mission's completed?

  55. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :) are u good in bio i need help?

  56. Callisto
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    i don't study Biology, sorry :(

  57. heena
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no prob :) u knw hydrocarbon?

  58. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.