anonymous
  • anonymous
How to create a quadratic equation when given is that one of the solutions must be 1/(3+2sqrt2) . Show steps.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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King
  • King
hw many times will u ask the same question?stop spamming!
anonymous
  • anonymous
Spamming? I didn't get an answer last time.
King
  • King
so wait u will get an answer..dont post the same question again

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anonymous
  • anonymous
y = (x- 1/(3+2sqrt2))(x-a) a can be anything
anonymous
  • anonymous
Thanks!
dumbcow
  • dumbcow
you could also rationalize it \[\frac{1}{3+2\sqrt{2}}*\frac{3-2\sqrt{2}}{3-2\sqrt{2}} = 3-2\sqrt{2}\] so then \[x = 3\pm 2\sqrt{2}\] \[x-3 = \pm2\sqrt{2}\] \[(x-3)^{2} = 8\] \[x^{2} -6x+1 = 0\]
anonymous
  • anonymous
Thank you!

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