anonymous
  • anonymous
If a projectile is launched vertically from the surface of the earth with a speed equal to the escape speed, how high above the Earth's surface is it when its peed is half the escape speed. Why can't I use the V=(GM(mass of the earth)/(R(earth+H))^(1/2)
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1332778632537:dw| apply conservation of energy:: total mechanical energy at surface=total mechanical energy at final 1/2m(Ve)^2=1/2m(Ve/2)^2+mgh.....find h from here....
anonymous
  • anonymous
I got it that way but I just dont get why I can't use the formula they give us to find it.
anonymous
  • anonymous
because of the magnitude of escape velocity is very high and due to which potential energy also be maximum that it reaches a distance which cant discard compare to radius of the earth...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ahhh
anonymous
  • anonymous
thx!
anonymous
  • anonymous
I wonder if I could apply this to the other question I posted
anonymous
  • anonymous
welcome...

Looking for something else?

Not the answer you are looking for? Search for more explanations.