anonymous
  • anonymous
how can I write 1*3*5*7...??
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
across
  • across
That could be interpreted two ways: 1. as the product of consecutive primes, or 2. as the product of consecutive odd integers.
across
  • across
;P
TuringTest
  • TuringTest
we could be fancy and write it with the \(\Pi\) notation :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

across
  • across
If it's the latter, then\[\prod_{i=0}^{\infty}2i+1\]
TuringTest
  • TuringTest
like that^
anonymous
  • anonymous
is as a product of odd numbers
across
  • across
Well, if it was the former, and you had an answer, then I would suggest that we get together. ;P
anonymous
  • anonymous
is just I have to write it in a general way is for a differential equation
TuringTest
  • TuringTest
but across, 1 is not prime and 2 is not on the list so it must be option 2, nno?
across
  • across
I am just messing around. ^^
anonymous
  • anonymous
A minor problem is that 1*3*5*7*... is meaningless.
anonymous
  • anonymous
Are you wondering how to express the first n terms? That would be (2*1-1)(2*2-1)(2*3-1)...(2*n-1)
anonymous
  • anonymous
yes just like that the thing is that I'm wondering is possible that I could write that like a factorial?
anonymous
  • anonymous
Not one factorial. But compare just the format through 7, with 7! and you have 1*2*3*4*5*6*7 as the factorial and 1*3*5*7 as the number you want. How do you get from the first to the second?
anonymous
  • anonymous
What happens when you divide the factorial by 2*4*6?
anonymous
  • anonymous
my equation is (x-1)y''-xy'+y=0 in my solution I have to state 1*3*5*7...in the series
anonymous
  • anonymous
Notice that 1*3*5*7 is 1*2*3*4*5*6*7 divided by 2*4*6. Both of these can be expressed using factorials.
anonymous
  • anonymous
I don't like just giving answers, but gotta run. The top is (2n+1)! for and the bottom is 2*n! for n=3.
anonymous
  • anonymous
Oh! you're si right!!! but how can you state that just in factorials? sorry is just I can't see how U_U
anonymous
  • anonymous
The nth term in your sequence is (2n+1)! / (2*n!)

Looking for something else?

Not the answer you are looking for? Search for more explanations.