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Rahul_gupta
 2 years ago
Best ResponseYou've already chosen the best response.0what to do wuth this question? Which Chapter Question??

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0i am in florida virtualll....

Rahul_gupta
 2 years ago
Best ResponseYou've already chosen the best response.0name the chapter or topic of your book from which this question u have asked!!

Laura*
 2 years ago
Best ResponseYou've already chosen the best response.4OK, so you're having trouble with the same stuff. 1) please don't keep repeatposting your questions. That's against our Code of Conduct 2) What specifically are you having trouble with. The entire theory?

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0sorry laura. Where can i check the code of cunduct so i dont make that mistake?

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0ok thank you . And are you like in charge of the program?

Laura*
 2 years ago
Best ResponseYou've already chosen the best response.4I'm one of the staff members here on site, yes.

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0ohh. And you asked me what i was having trouble with... mostly with the entriel theory of logs actuall :S

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0do you think you can help me with logs?

Laura*
 2 years ago
Best ResponseYou've already chosen the best response.4No, I really can't help with logs. Sorry. I don't remember most of this math....

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh, do who know any group member that can help me with this?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0@sofia I'd help you. Do you need an explanation on logarithms?

Shayaan_Mustafa
 2 years ago
Best ResponseYou've already chosen the best response.1@sofia_smr What help you want with logs?

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.0Take LN on both sides: Ln(3^(x4))=Ln(7^(x+9)) Using the property Lna^b=b*Lna: (x4)Ln3=(x+9)Ln7

Rihanna
 2 years ago
Best ResponseYou've already chosen the best response.0Input Interpretation: solve ; 3 ^ x4 = 7 ^ x+9 Results: this soo hard to type because of lag and error equation so i post a site that just show you the answer and hopefully you know how to do the equation http://www.wolframalpha.com/bing/?i=solve+3%5e(x++4)+%3d+7%5e(x+%2b+9)&expl=3

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0i cant understand pretty much everything about them :S

Rihanna
 2 years ago
Best ResponseYou've already chosen the best response.0it shows results, real solution and plot.

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.0Distribute and simplify.. i gotta go to class bbl

Shayaan_Mustafa
 2 years ago
Best ResponseYou've already chosen the best response.13^(x4)=7^(x+9) Take the natural logarithm of both sides of the equation to remove the variable from the exponent. ln(3^(x4))=ln(7^(x+9)) The lefthand side of the equation is equal to the exponent of the logarithm argument because the base of the logarithm equals the base of the argument. xln(3)4ln(3)=ln(7^(x+9)) The exponent of a factor inside a logarithm can be expanded to the front of the expression using the third law of logarithms. The third law of logarithms states that the logarithm of a power of x is equal to the exponent of that power times the logarithm of x (e.g. log^b(x^(n))=nlog^b(x)). xln(3)4ln(3)=((x+9)ln(7)) Multiply ln(7) by each term inside the parentheses. xln(3)4ln(3)=(xln(7)+9ln(7)) Since xln(7) contains the variable to solve for, move it to the lefthand side of the equation by subtracting xln(7) from both sides. xln(3)4ln(3)xln(7)=9ln(7) Factor out the GCF of x from each term in the polynomial. x(ln(3))+x(ln(7))=4ln(3)+9ln(7) Factor out the GCF of x from xln(3)xln(7). x(ln(3)ln(7))=4ln(3)+9ln(7) Divide each term in the equation by (ln(3)ln(7)). (x(ln(3)ln(7)))/(ln(3)ln(7))=(4ln(3))/(ln(3)ln(7))+(9ln(7))/(ln(3)ln(7)) Simplify the lefthand side of the equation by canceling the common factors. x=(4ln(3))/(ln(3)ln(7))+(9ln(7))/(ln(3)ln(7)) Simplify the righthand side of the equation by simplifying each term. x=(4ln(3)+9ln(7))/(ln(3)ln(7))

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks a lot though, good luck

Rihanna
 2 years ago
Best ResponseYou've already chosen the best response.0(x4)log3 = (x+9)log7 Sofia, sorry i don't gotta calculator :/

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0@sofia_smr Did you understand?

sofia_smr
 2 years ago
Best ResponseYou've already chosen the best response.0yes! shaayaan gave me a great example there!

Rihanna
 2 years ago
Best ResponseYou've already chosen the best response.0glad you got help by someone :)
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