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sofia_smr

  • 4 years ago

Solve 3^(x – 4) = 7^(x + 9)

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  1. Rahul_gupta
    • 4 years ago
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    what to do wuth this question? Which Chapter Question??

  2. sofia_smr
    • 4 years ago
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    i am in florida virtualll....

  3. Rahul_gupta
    • 4 years ago
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    name the chapter or topic of your book from which this question u have asked!!

  4. Laura*
    • 4 years ago
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    OK, so you're having trouble with the same stuff. 1) please don't keep repeat-posting your questions. That's against our Code of Conduct 2) What specifically are you having trouble with. The entire theory?

  5. sofia_smr
    • 4 years ago
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    sorry laura. Where can i check the code of cunduct so i dont make that mistake?

  6. Laura*
    • 4 years ago
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    http://openstudy.com/code-of-conduct

  7. sofia_smr
    • 4 years ago
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    ok thank you . And are you like in charge of the program?

  8. Laura*
    • 4 years ago
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    I'm one of the staff members here on site, yes.

  9. sofia_smr
    • 4 years ago
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    ohh. And you asked me what i was having trouble with... mostly with the entriel theory of logs actuall :S

  10. sofia_smr
    • 4 years ago
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    do you think you can help me with logs?

  11. Laura*
    • 4 years ago
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    No, I really can't help with logs. Sorry. I don't remember most of this math....

  12. sofia_smr
    • 4 years ago
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    ohhh, do who know any group member that can help me with this?

  13. ash2326
    • 4 years ago
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    @sofia I'd help you. Do you need an explanation on logarithms?

  14. Shayaan_Mustafa
    • 4 years ago
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    @sofia_smr What help you want with logs?

  15. bahrom7893
    • 4 years ago
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    Take LN on both sides: Ln(3^(x-4))=Ln(7^(x+9)) Using the property Lna^b=b*Lna: (x-4)Ln3=(x+9)Ln7

  16. Rihanna
    • 4 years ago
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    Input Interpretation: solve ; 3 ^ x-4 = 7 ^ x+9 Results: this soo hard to type because of lag and error equation so i post a site that just show you the answer and hopefully you know how to do the equation http://www.wolframalpha.com/bing/?i=solve+3%5e(x+-+4)+%3d+7%5e(x+%2b+9)&expl=3

  17. sofia_smr
    • 4 years ago
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    i cant understand pretty much everything about them :S

  18. Rihanna
    • 4 years ago
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    it shows results, real solution and plot.

  19. bahrom7893
    • 4 years ago
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    Distribute and simplify.. i gotta go to class bbl

  20. Shayaan_Mustafa
    • 4 years ago
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    3^(x-4)=7^(x+9) Take the natural logarithm of both sides of the equation to remove the variable from the exponent. ln(3^(x-4))=ln(7^(x+9)) The left-hand side of the equation is equal to the exponent of the logarithm argument because the base of the logarithm equals the base of the argument. xln(3)-4ln(3)=ln(7^(x+9)) The exponent of a factor inside a logarithm can be expanded to the front of the expression using the third law of logarithms. The third law of logarithms states that the logarithm of a power of x is equal to the exponent of that power times the logarithm of x (e.g. log^b(x^(n))=nlog^b(x)). xln(3)-4ln(3)=((x+9)ln(7)) Multiply ln(7) by each term inside the parentheses. xln(3)-4ln(3)=(xln(7)+9ln(7)) Since xln(7) contains the variable to solve for, move it to the left-hand side of the equation by subtracting xln(7) from both sides. xln(3)-4ln(3)-xln(7)=9ln(7) Factor out the GCF of x from each term in the polynomial. x(ln(3))+x(-ln(7))=4ln(3)+9ln(7) Factor out the GCF of x from xln(3)-xln(7). x(ln(3)-ln(7))=4ln(3)+9ln(7) Divide each term in the equation by (ln(3)-ln(7)). (x(ln(3)-ln(7)))/(ln(3)-ln(7))=(4ln(3))/(ln(3)-ln(7))+(9ln(7))/(ln(3)-ln(7)) Simplify the left-hand side of the equation by canceling the common factors. x=(4ln(3))/(ln(3)-ln(7))+(9ln(7))/(ln(3)-ln(7)) Simplify the right-hand side of the equation by simplifying each term. x=(4ln(3)+9ln(7))/(ln(3)-ln(7))

  21. sofia_smr
    • 4 years ago
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    ok thanks a lot though, good luck

  22. Rihanna
    • 4 years ago
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    (x-4)log3 = (x+9)log7 Sofia, sorry i don't gotta calculator :/

  23. ash2326
    • 4 years ago
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    @sofia_smr Did you understand?

  24. sofia_smr
    • 4 years ago
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    yes! shaayaan gave me a great example there!

  25. Shayaan_Mustafa
    • 4 years ago
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    Thanks.

  26. Rihanna
    • 4 years ago
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    glad you got help by someone :)

  27. sofia_smr
    • 4 years ago
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    thanks guys!

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