Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Rahul_gupta Group TitleBest ResponseYou've already chosen the best response.0
what to do wuth this question? Which Chapter Question??
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
i am in florida virtualll....
 2 years ago

Rahul_gupta Group TitleBest ResponseYou've already chosen the best response.0
name the chapter or topic of your book from which this question u have asked!!
 2 years ago

Laura* Group TitleBest ResponseYou've already chosen the best response.4
OK, so you're having trouble with the same stuff. 1) please don't keep repeatposting your questions. That's against our Code of Conduct 2) What specifically are you having trouble with. The entire theory?
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
sorry laura. Where can i check the code of cunduct so i dont make that mistake?
 2 years ago

Laura* Group TitleBest ResponseYou've already chosen the best response.4
http://openstudy.com/codeofconduct
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
ok thank you . And are you like in charge of the program?
 2 years ago

Laura* Group TitleBest ResponseYou've already chosen the best response.4
I'm one of the staff members here on site, yes.
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
ohh. And you asked me what i was having trouble with... mostly with the entriel theory of logs actuall :S
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
do you think you can help me with logs?
 2 years ago

Laura* Group TitleBest ResponseYou've already chosen the best response.4
No, I really can't help with logs. Sorry. I don't remember most of this math....
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
ohhh, do who know any group member that can help me with this?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
@sofia I'd help you. Do you need an explanation on logarithms?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
@sofia_smr What help you want with logs?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Take LN on both sides: Ln(3^(x4))=Ln(7^(x+9)) Using the property Lna^b=b*Lna: (x4)Ln3=(x+9)Ln7
 2 years ago

Rihanna Group TitleBest ResponseYou've already chosen the best response.0
Input Interpretation: solve ; 3 ^ x4 = 7 ^ x+9 Results: this soo hard to type because of lag and error equation so i post a site that just show you the answer and hopefully you know how to do the equation http://www.wolframalpha.com/bing/?i=solve+3%5e(x++4)+%3d+7%5e(x+%2b+9)&expl=3
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
i cant understand pretty much everything about them :S
 2 years ago

Rihanna Group TitleBest ResponseYou've already chosen the best response.0
it shows results, real solution and plot.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Distribute and simplify.. i gotta go to class bbl
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
3^(x4)=7^(x+9) Take the natural logarithm of both sides of the equation to remove the variable from the exponent. ln(3^(x4))=ln(7^(x+9)) The lefthand side of the equation is equal to the exponent of the logarithm argument because the base of the logarithm equals the base of the argument. xln(3)4ln(3)=ln(7^(x+9)) The exponent of a factor inside a logarithm can be expanded to the front of the expression using the third law of logarithms. The third law of logarithms states that the logarithm of a power of x is equal to the exponent of that power times the logarithm of x (e.g. log^b(x^(n))=nlog^b(x)). xln(3)4ln(3)=((x+9)ln(7)) Multiply ln(7) by each term inside the parentheses. xln(3)4ln(3)=(xln(7)+9ln(7)) Since xln(7) contains the variable to solve for, move it to the lefthand side of the equation by subtracting xln(7) from both sides. xln(3)4ln(3)xln(7)=9ln(7) Factor out the GCF of x from each term in the polynomial. x(ln(3))+x(ln(7))=4ln(3)+9ln(7) Factor out the GCF of x from xln(3)xln(7). x(ln(3)ln(7))=4ln(3)+9ln(7) Divide each term in the equation by (ln(3)ln(7)). (x(ln(3)ln(7)))/(ln(3)ln(7))=(4ln(3))/(ln(3)ln(7))+(9ln(7))/(ln(3)ln(7)) Simplify the lefthand side of the equation by canceling the common factors. x=(4ln(3))/(ln(3)ln(7))+(9ln(7))/(ln(3)ln(7)) Simplify the righthand side of the equation by simplifying each term. x=(4ln(3)+9ln(7))/(ln(3)ln(7))
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
ok thanks a lot though, good luck
 2 years ago

Rihanna Group TitleBest ResponseYou've already chosen the best response.0
(x4)log3 = (x+9)log7 Sofia, sorry i don't gotta calculator :/
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
@sofia_smr Did you understand?
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
yes! shaayaan gave me a great example there!
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
Thanks.
 2 years ago

Rihanna Group TitleBest ResponseYou've already chosen the best response.0
glad you got help by someone :)
 2 years ago

sofia_smr Group TitleBest ResponseYou've already chosen the best response.0
thanks guys!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.