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 2 years ago
Prove that the product of 4 consecutive integers is 1 less than a perfect square.
 2 years ago
Prove that the product of 4 consecutive integers is 1 less than a perfect square.

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FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.4what have you tried?

ZombiePig
 2 years ago
Best ResponseYou've already chosen the best response.0oops type0! :( \[n(n+1)(n+2)(n+3)\]

2bornot2b
 2 years ago
Best ResponseYou've already chosen the best response.0Tried many things in vain

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.4Kidds stuffs, Let the consecutive integers be \( (n  1), n, (n + 1), (n + 2) \) Expanding: \[n^4 + 2n^3  n^2  2n= (n^2 + n  1)^21 \]
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