Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing
2bornot2b
Group Title
Prove that the product of 4 consecutive integers is 1 less than a perfect square.
 2 years ago
 2 years ago
2bornot2b Group Title
Prove that the product of 4 consecutive integers is 1 less than a perfect square.
 2 years ago
 2 years ago

This Question is Closed

FoolForMath Group TitleBest ResponseYou've already chosen the best response.4
what have you tried?
 2 years ago

ZombiePig Group TitleBest ResponseYou've already chosen the best response.0
oops type0! :( \[n(n+1)(n+2)(n+3)\]
 2 years ago

2bornot2b Group TitleBest ResponseYou've already chosen the best response.0
Tried many things in vain
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.4
Kidds stuffs, Let the consecutive integers be \( (n  1), n, (n + 1), (n + 2) \) Expanding: \[n^4 + 2n^3  n^2  2n= (n^2 + n  1)^21 \]
 2 years ago

ZombiePig Group TitleBest ResponseYou've already chosen the best response.0
Nice work ffm!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.