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hello tishagwen. are you there?
sorry yea im here
and its mrs.. ")
oh .. hehehehhehe... mrs. or right. let us solve it. Well I don't know how to use arrays on this site. so kindly. try to understand me.
the problem changed sorry
yes. what is it?
miss it is the same question that you've posted.
if i understand right.. ill need to take the first set and multiply by 5 and the the 2nd one multiply by-1 right?
no no. here you are solving the equation with Gauss elimination method(Echelon form).
so first write equation as matrices form. 1 1 10 5 -1 44 OK?
ok now Replace row 2 (i.e. R2) with the row operation R2 new=-4*R1+R2 in order to convert some elements in the row into the desired value 0.
do this step. then tell me.
no no my dear.
do the row operation on R2(row 2)
what do you mean
means. multiply R1 with 4 and minus it from R2 i.e. R2new=R2-4R1 Does this make sense to you?
not really i know nothing of the matrix stuff
now look at pic and here I am going to solve it for you. keep the pic in mind. OK
how did u get 4 i thought it was 5
yes yes it is 5 sorry. it is a mistake.
step#2) multiply R1 with 5|dw:1332792360847:dw|
Did you get step#2?
x+y=10,5x-y=44 Write the system of equations in matrix form. M[1,1,10:5,-1,44] Replace row 2 (i.e. R2) with the row operation R2 new=-5*R1+R2 in order to convert some elements in the row into the desired value 0. M[1,1,10:0,-6,-6] Replace row 2 (i.e. R2) with the row operation R2 new=-(1)/(6)*R2 in order to convert some elements in the row into the desired value 1. M[1,1,10:0,1,1] Replace row 1 (i.e. R1) with the row operation R1 new=-1*R2+R1 in order to convert some elements in the row into the desired value 0. M[1,0,9:0,1,1] Use the result matrix to declare the final solutions to the system of equations. x=9_y=1 This expression is the solution set for the system of equations. (9,1)
Here is your all solution. good luck.
would it be 1 0 9 0 1 1
ok, I think i got it now.. thank you so much!
you are ever welcome.