anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
this is one of those discrete recurrence relations that can be modeled by Pert i think
anonymous
  • anonymous
1= 10 (1/2)^(t/24) Solve for t 0.1 = (1/2)^(t/24) ln (0.1) = (t/24,360) ln(0.5) t/24,360 = ln(0.1) / ln(0.5) t = 24,360 ln(0.1) / ln(0.5) t= 80922.1683 80,922 years
amistre64
  • amistre64
ln(2)/24,360 = r 1 = 10e^(ln(2)/24360 * t) .1 = e^(ln(2)/24360 * t) ln(.1) = ln(2)/24360 * t ln(.1)/ln(2) = t/24360 24360ln(.1)/ln(2) = t would be my guess if i did my mathing right

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amistre64
  • amistre64
there are a few ways to go about it, so that migh tbe a plausible method
amistre64
  • amistre64
there are other sites?
amistre64
  • amistre64
the answer i found looks to model the e^x graph so it says t is negtaive; but the negative part can simply be ignored
amistre64
  • amistre64
well, it should be about 80922 im not quite sure how your using the calculator tho :)
amistre64
  • amistre64
http://www.google.com/#hl=en&sugexp=llsin&gs_nf=1&pq=24360ln(.1)%2Fln(2)&cp=19&gs_id=1p&xhr=t&q=10(1/2)%5E(t/24360)-1&pf=p&sclient=psy-ab&oq=10(1/2)%5E(t/24360)-1&aq=&aqi=&aql=&gs_l=&pbx=1&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&fp=81eee28ba52115e6&biw=1280&bih=930 google gives a graph now, thats pretty cool
anonymous
  • anonymous
....
amistre64
  • amistre64
its even got a tracker on it lol
amistre64
  • amistre64
you should but it might get squiched on the screen, i aint got me ti83 with me to test out tho
amistre64
  • amistre64
yw
anonymous
  • anonymous
@kk alright fine...i guess
anonymous
  • anonymous
yourwelcome..
amistre64
  • amistre64
i see you edited to a "."
anonymous
  • anonymous
@rihanna, come
anonymous
  • anonymous
Mhmm?

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