anonymous
  • anonymous
What is the distance between the zoo and the library? (Adding the rest of the things to answers this)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Max observes the zoo and the library from a helicopter flying at a height of \[400\sqrt{3}\]feet above the ground
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mysesshou
  • mysesshou
Hehe. I just did one similar. For an extra example, you can check this out later. http://openstudy.com/study#/updates/4f70e051e4b0eb8587736748
mysesshou
  • mysesshou
Ok, give a sec to read through.

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mysesshou
  • mysesshou
|dw:1332799443526:dw|
mysesshou
  • mysesshou
using this, we can solve for the sides, using your given values.
mysesshou
  • mysesshou
Let's first find the length of G to Zoo.
anonymous
  • anonymous
\[400 \sqrt{3}(\text{Cot}[30{}^{\circ}]-\text{Cot}[60{}^{\circ}])\text{=}400 \sqrt{3} \left(-\frac{1}{\sqrt{3}}+\sqrt{3}\right)=800 \text{ft}\]
mysesshou
  • mysesshou
|dw:1332799547590:dw|
mysesshou
  • mysesshou
Then, G to Library, and we take the difference. Cjcj do you know trig and sin, cos, tan ?
mysesshou
  • mysesshou
have you seen the things I've posed previously? I'm hoping to find the same method you've been learning
anonymous
  • anonymous
I know sin cos and tan yes.
mysesshou
  • mysesshou
Ok, then, robtobey's method works too. Whichever is simplest for you.
mysesshou
  • mysesshou
But to finish, |dw:1332799945753:dw| |dw:1332800034265:dw|
mysesshou
  • mysesshou
I wasn't sure how much trig (sin, cos, tan) was in geo :)
anonymous
  • anonymous
I have a few Qs just so I understand this myself. I see 60deg and 30deg. Am I to assume that 'Zoo' is halfway inbetween G and Library?
mysesshou
  • mysesshou
No., zoo not halfway.
mysesshou
  • mysesshou
which is why sometimes, they say "drawings not to scale"
mysesshou
  • mysesshou
to scale, would have my last picture as more accurate than the one they gave you in the HW.
anonymous
  • anonymous
and how does 400sqrt3 turn into 5sqrt3 in the picture above you drew?
mysesshou
  • mysesshou
It's supposed to be an s not 5. sorry
mysesshou
  • mysesshou
you're solving for the S
mysesshou
  • mysesshou
robtobey's method is probably simplest, if you know the trig functions :)
mysesshou
  • mysesshou
then you don't have to draw out the two triangles.
anonymous
  • anonymous
ohhhh okay I got it now. And yeah id much rather draw the triangles out. I hate trig haha
mysesshou
  • mysesshou
but note that those dimensions only works for a 30 60 90 triangle. There is another one for 45 45 90 triangles. if the one you are solving is not of those angles, then you use the sin, cos, tan |dw:1332800590264:dw| ok, I used X instead of S to tell the difference
anonymous
  • anonymous
that's an arrow on the bottom nextt to 45 right
mysesshou
  • mysesshou
Yes, attempting to point that 45 is the lower right corner. For some reason, my drawing feature isn't acting as nicely today O_O
mysesshou
  • mysesshou
I added the trig to that other example, if you wanted to see more trig... since that other person's was the final result in one equation. http://openstudy.com/study#/updates/4f70e051e4b0eb8587736748
mysesshou
  • mysesshou
It is hard to know people's levels, since there are multiple ways of solving :)
anonymous
  • anonymous
Lol its okay, and ill look at the link when I finish my test in a second. Have to have 4 assignments in by 7 and thats in 20 mins :p
mysesshou
  • mysesshou
Ouch. Maybe let us know you're on a time limit next time, and I won't babble :) good luck.
anonymous
  • anonymous
I have to find the height of AB. I got 180m
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anonymous
  • anonymous
and you arent babbling / time limit doesnt matter to much because usually I can get tests done before the time is called with no problem.
mysesshou
  • mysesshou
i think i get 90*tan(30) = 51.96 but my new calc works in radians, so make sure it is right. can't fig out how to change to degrees
mysesshou
  • mysesshou
because 30 deg, then AB is smaller. try drawing it to scale yourself. it is simpler to see
mysesshou
  • mysesshou
because 30 deg, then AB is smaller than CB |dw:1332802425507:dw|
mysesshou
  • mysesshou
dug out old calculator. i still get 51.96 how did you get yours?
anonymous
  • anonymous
im trying to upload it from my phone right now
anonymous
  • anonymous
(picture of my work)
mysesshou
  • mysesshou
ok, well , hope you finish in time
mysesshou
  • mysesshou
or work on your other problems?
anonymous
  • anonymous
did u come up with 30sqrt3 or 90sqrt3 in any of your works trying to find the height?
anonymous
  • anonymous
come across*
mysesshou
  • mysesshou
* tan30 = 1/sqrt3 I think it is 90/sqrt3 = 51.96
mysesshou
  • mysesshou
90/sqrt3 = 51.96 = 90*tan(30)
anonymous
  • anonymous
Ahh okay. Apparently the school system doesnt want 'over-simplification'
mysesshou
  • mysesshou
is it multple choice?
anonymous
  • anonymous
This question was a fill in the blank.
mysesshou
  • mysesshou
even my triangle method, i get height = 90/sqrt3
mysesshou
  • mysesshou
hope you're not too late. it is 7:06 !
anonymous
  • anonymous
This question was for an assignment due tomorrow haha thank god. But I came across the 9-/sqrt3 and 180m before I asked you. I was going to go with the 18- because the 1st one didnt look right to me but I guess I was wrong.
mysesshou
  • mysesshou
crazy website keeps loosing connection... maybe you need units, 51.96 m ?
mysesshou
  • mysesshou
*losing
mysesshou
  • mysesshou
|dw:1332803573813:dw|
anonymous
  • anonymous
Yeah it keeps bumping me out or d/cing and the answer is correct, but they wanted it in the sqrt form. If they wanted a measurement they would have added (m for meters) at the end of the blank
mysesshou
  • mysesshou
ok, so they tell you that 90/sqrt3 is right. that is good. i guess you just have to know that tan30=1/sqrt3
mysesshou
  • mysesshou
have you memorized the unit circle? I used to know it all, and that was a big help then. I don't have it memorized anymore. :(
anonymous
  • anonymous
http://www.mathpeer.com/images/trig/unit_circle.gif ?
mysesshou
  • mysesshou
yep
anonymous
  • anonymous
No I don't have it memorized lol
mysesshou
  • mysesshou
:) helpful, when the calculator gives decimal answers. unless you get a TI89 or something like that.
mysesshou
  • mysesshou
interesting. I put it in 89 and get 30*sqrt3. i suppose that is simplified more. 90*sqrt3 / (sqrt3 * sqrt3) then it is (90/3) * sqrt3
mysesshou
  • mysesshou
so if this one was for tomorrow, were you able to finish today's ok? :)
mysesshou
  • mysesshou
I guess I'll leave campus now unless you have another Q. :)
anonymous
  • anonymous
Haha I got everything in. Im just going to post a few problems with my answers to see if other people got what I got. (Not these problems other problems obv) Thanks for the help!
mysesshou
  • mysesshou
Ok, you're welcome. :)

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