What is the distance between the zoo and the library?
(Adding the rest of the things to answers this)

- anonymous

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- anonymous

Max observes the zoo and the library from a helicopter flying at a height of \[400\sqrt{3}\]feet above the ground

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- mysesshou

Hehe. I just did one similar. For an extra example, you can check this out later. http://openstudy.com/study#/updates/4f70e051e4b0eb8587736748

- mysesshou

Ok, give a sec to read through.

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- mysesshou

|dw:1332799443526:dw|

- mysesshou

using this, we can solve for the sides, using your given values.

- mysesshou

Let's first find the length of G to Zoo.

- anonymous

\[400 \sqrt{3}(\text{Cot}[30{}^{\circ}]-\text{Cot}[60{}^{\circ}])\text{=}400 \sqrt{3} \left(-\frac{1}{\sqrt{3}}+\sqrt{3}\right)=800 \text{ft}\]

- mysesshou

|dw:1332799547590:dw|

- mysesshou

Then, G to Library, and we take the difference.
Cjcj do you know trig and sin, cos, tan ?

- mysesshou

have you seen the things I've posed previously?
I'm hoping to find the same method you've been learning

- anonymous

I know sin cos and tan yes.

- mysesshou

Ok, then, robtobey's method works too. Whichever is simplest for you.

- mysesshou

But to finish,
|dw:1332799945753:dw|
|dw:1332800034265:dw|

- mysesshou

I wasn't sure how much trig (sin, cos, tan) was in geo :)

- anonymous

I have a few Qs just so I understand this myself. I see 60deg and 30deg. Am I to assume that 'Zoo' is halfway inbetween G and Library?

- mysesshou

No., zoo not halfway.

- mysesshou

which is why sometimes, they say "drawings not to scale"

- mysesshou

to scale, would have my last picture as more accurate than the one they gave you in the HW.

- anonymous

and how does 400sqrt3 turn into 5sqrt3 in the picture above you drew?

- mysesshou

It's supposed to be an s not 5. sorry

- mysesshou

you're solving for the S

- mysesshou

robtobey's method is probably simplest, if you know the trig functions :)

- mysesshou

then you don't have to draw out the two triangles.

- anonymous

ohhhh okay I got it now. And yeah id much rather draw the triangles out. I hate trig haha

- mysesshou

but note that those dimensions only works for a 30 60 90 triangle. There is another one for 45 45 90 triangles.
if the one you are solving is not of those angles, then you use the sin, cos, tan
|dw:1332800590264:dw|
ok, I used X instead of S to tell the difference

- anonymous

that's an arrow on the bottom nextt to 45 right

- mysesshou

Yes, attempting to point that 45 is the lower right corner. For some reason, my drawing feature isn't acting as nicely today O_O

- mysesshou

I added the trig to that other example, if you wanted to see more trig... since that other person's was the final result in one equation.
http://openstudy.com/study#/updates/4f70e051e4b0eb8587736748

- mysesshou

It is hard to know people's levels, since there are multiple ways of solving :)

- anonymous

Lol its okay, and ill look at the link when I finish my test in a second. Have to have 4 assignments in by 7 and thats in 20 mins :p

- mysesshou

Ouch. Maybe let us know you're on a time limit next time, and I won't babble :) good luck.

- anonymous

I have to find the height of AB. I got 180m

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- anonymous

and you arent babbling / time limit doesnt matter to much because usually I can get tests done before the time is called with no problem.

- mysesshou

i think i get 90*tan(30) = 51.96
but my new calc works in radians, so make sure it is right. can't fig out how to change to degrees

- mysesshou

because 30 deg, then AB is smaller. try drawing it to scale yourself. it is simpler to see

- mysesshou

because 30 deg, then AB is smaller than CB
|dw:1332802425507:dw|

- mysesshou

dug out old calculator. i still get 51.96
how did you get yours?

- anonymous

im trying to upload it from my phone right now

- anonymous

(picture of my work)

- mysesshou

ok, well , hope you finish in time

- mysesshou

or work on your other problems?

- anonymous

did u come up with 30sqrt3 or 90sqrt3 in any of your works trying to find the height?

- anonymous

come across*

- mysesshou

* tan30 = 1/sqrt3
I think it is 90/sqrt3 = 51.96

- mysesshou

90/sqrt3 = 51.96 = 90*tan(30)

- anonymous

Ahh okay. Apparently the school system doesnt want 'over-simplification'

- mysesshou

is it multple choice?

- anonymous

This question was a fill in the blank.

- mysesshou

even my triangle method, i get height = 90/sqrt3

- mysesshou

hope you're not too late. it is 7:06 !

- anonymous

This question was for an assignment due tomorrow haha thank god. But I came across the 9-/sqrt3 and 180m before I asked you. I was going to go with the 18- because the 1st one didnt look right to me but I guess I was wrong.

- mysesshou

crazy website keeps loosing connection...
maybe you need units, 51.96 m ?

- mysesshou

*losing

- mysesshou

|dw:1332803573813:dw|

- anonymous

Yeah it keeps bumping me out or d/cing and the answer is correct, but they wanted it in the sqrt form. If they wanted a measurement they would have added (m for meters) at the end of the blank

- mysesshou

ok, so they tell you that 90/sqrt3 is right. that is good.
i guess you just have to know that tan30=1/sqrt3

- mysesshou

have you memorized the unit circle? I used to know it all, and that was a big help then. I don't have it memorized anymore. :(

- anonymous

http://www.mathpeer.com/images/trig/unit_circle.gif ?

- mysesshou

yep

- anonymous

No I don't have it memorized lol

- mysesshou

:) helpful, when the calculator gives decimal answers. unless you get a TI89 or something like that.

- mysesshou

interesting. I put it in 89 and get 30*sqrt3. i suppose that is simplified more.
90*sqrt3 / (sqrt3 * sqrt3)
then it is (90/3) * sqrt3

- mysesshou

so if this one was for tomorrow, were you able to finish today's ok? :)

- mysesshou

I guess I'll leave campus now unless you have another Q. :)

- anonymous

Haha I got everything in. Im just going to post a few problems with my answers to see if other people got what I got. (Not these problems other problems obv) Thanks for the help!

- mysesshou

Ok, you're welcome. :)

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