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greeneyes<3
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You buy a computer for $1200. The value of the computer decreases by 30% each year. Find the value of the computer after 4 years.
Please show work! Thanks!
 2 years ago
 2 years ago
greeneyes<3 Group Title
You buy a computer for $1200. The value of the computer decreases by 30% each year. Find the value of the computer after 4 years. Please show work! Thanks!
 2 years ago
 2 years ago

This Question is Closed

marshallinwashington Group TitleBest ResponseYou've already chosen the best response.1
Let c = value of computer in dollars. Let t= the number of years \[c=1200e ^{.3t}\]\[c=1200e ^{.3(4)}\] c= $361.43
 2 years ago

greeneyes<3 Group TitleBest ResponseYou've already chosen the best response.1
Thanks the only thing is that my teacher got the answer: $288.12
 2 years ago

greeneyes<3 Group TitleBest ResponseYou've already chosen the best response.1
Sometimes he is wrong though...
 2 years ago

marshallinwashington Group TitleBest ResponseYou've already chosen the best response.1
He probably using a linear equation instead of an exponential. Have you discussed logarithms?
 2 years ago

greeneyes<3 Group TitleBest ResponseYou've already chosen the best response.1
We did logarithms about 2 months ago.
 2 years ago

marshallinwashington Group TitleBest ResponseYou've already chosen the best response.1
Check back a little while and I'll see if I can come up with the linear equation
 2 years ago

greeneyes<3 Group TitleBest ResponseYou've already chosen the best response.1
okay you can take your time :) really, thanks for helping me. It does mean a lot. :)
 2 years ago

marshallinwashington Group TitleBest ResponseYou've already chosen the best response.1
It's not a linear equation, but an exponential equation. \[c=1200(.7)^{t}\] So for t=4 years \[c=1200(.7)^{4}\] Which gives us $288.12 The difference between the first equation I wrote and the new one is that in the first one the computer lost value continuously.
 2 years ago

greeneyes<3 Group TitleBest ResponseYou've already chosen the best response.1
Thank you so much!!! ^_^
 2 years ago
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