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anonymous
 4 years ago
You buy a computer for $1200. The value of the computer decreases by 30% each year. Find the value of the computer after 4 years.
Please show work! Thanks!
anonymous
 4 years ago
You buy a computer for $1200. The value of the computer decreases by 30% each year. Find the value of the computer after 4 years. Please show work! Thanks!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let c = value of computer in dollars. Let t= the number of years \[c=1200e ^{.3t}\]\[c=1200e ^{.3(4)}\] c= $361.43

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks the only thing is that my teacher got the answer: $288.12

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sometimes he is wrong though...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0He probably using a linear equation instead of an exponential. Have you discussed logarithms?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We did logarithms about 2 months ago.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Check back a little while and I'll see if I can come up with the linear equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay you can take your time :) really, thanks for helping me. It does mean a lot. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's not a linear equation, but an exponential equation. \[c=1200(.7)^{t}\] So for t=4 years \[c=1200(.7)^{4}\] Which gives us $288.12 The difference between the first equation I wrote and the new one is that in the first one the computer lost value continuously.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much!!! ^_^
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