anonymous
  • anonymous
5. A rocket is launched from atop a 105-foot cliff with an initial velocity of 156 ft/s. The height of the rocket above the ground at time t is given by h = –16t2 + 156t + 105. When will the rocket hit the ground after it is launched? Round to the nearest tenth of a second. (1 point) 4.9 s 9.8 s 0.6 s 10.4 s
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[h = –16t^2 + 156t + 105\] hits the ground when h = 0 solve \[0 = –16t^2 + 156t + 105\]
anonymous
  • anonymous
you need method or just the answer?
anonymous
  • anonymous
i get 10.38 rounded, or 10.4

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anonymous
  • anonymous
this is an old one
anonymous
  • anonymous
@satellite73 Thank you so much for showing the method for solving this and not just the answer! :)

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