anonymous
  • anonymous
Solve for x:
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Solve for x:
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
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Mertsj
  • Mertsj
Multiply all terms by the common denominator which is 21x(x+4)
Mertsj
  • Mertsj
Remember that x cannot be 0 or -4

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anonymous
  • anonymous
then no solution
Mertsj
  • Mertsj
I got x = 3
anonymous
  • anonymous
lest's satrt with the left hand side L.H.S=(3x+12+3x)/(3x^2+12x) then we multiply l.h.s with r.h.s to get 21x^2+84x+21x^2=30x^2+120x therefore 42x^2+84x=30x^2+120x so 12x^2=36x ................ therefore........... 12x^2-36x=0 so.... 12x(x-3)=0 therfore (X=0) Refused.............or........... x=3
Mertsj
  • Mertsj
\[21x(x+4)\times\frac{3}{3x}+21x(x+4)\times\frac{1}{x+4}=\frac{10}{7x}\times \times21x(x+4)\]
Mertsj
  • Mertsj
\[7(x+4)(3)+21x(1)=10(3)(x+4)\]
Mertsj
  • Mertsj
\[21x+84+21x=30x+120\]
Mertsj
  • Mertsj
\[42x+84=30x=120\]
Mertsj
  • Mertsj
\[12x=36\]
Mertsj
  • Mertsj
\[x=3\]

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