lilai3
  • lilai3
Can someone please help me...please? How many ways can 6 students be arranged in a lunch line? A family has a bike rack that fits 7 bikes but they only have 5 bikes. How many ways can the bikes fit in the bike rack? How many 4-digit pin numbers are available if no number is repeated?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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lilai3
  • lilai3
helllpp mee please!!!!!!
anonymous
  • anonymous
lunch line: 6! = 720
lilai3
  • lilai3
thhaaaannnnkkk yoooouuuuu ,and also the other problems... and could you possibly explain to me plz? (i'll give u a meeedddaaalll?????????) >:D

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More answers

anonymous
  • anonymous
it's the formula such that having x to arranged, then we have x factorial (x!) so if it's 10 students then 10!. 20 will be 20!, and so on
anonymous
  • anonymous
pin number we have 10 digits number 0-9 so we can choose the first number from 10 numbers then we choose the 2nd number from 9 numbers (since no number repeated) then we choose the 3rd number from 8 numbers then we choose the last number from 7 numbers left finally we have: 10*9*8*7 = 5040
anonymous
  • anonymous
we the numbers is allowed to be repeated, then we have 10 ways to choose each number, and so: 10*10*10*10 = 10^4 = 10000
lilai3
  • lilai3
wait... r u talking about the bike one?
anonymous
  • anonymous
no the pin number
lilai3
  • lilai3
oh... so then the real answer's suppose to be 10000... rite?
anonymous
  • anonymous
no the answer for your pin number is 5040 the 10000 is the insight idea
lilai3
  • lilai3
oh i get it now.. so If the numbers can be repeated, dat means dat dere are 10,000 possiblities, correct?
anonymous
  • anonymous
yes
lilai3
  • lilai3
so then wut about the biking one?
anonymous
  • anonymous
do you know about permutation?
lilai3
  • lilai3
ya
lilai3
  • lilai3
is it 7*6*5*4*3=2520?
anonymous
  • anonymous
yes, the same result if you apply 7P5 = 7!/(7-5)!
lilai3
  • lilai3
oh, okay then and thank you but i also haf 2 more questions if u don't mind: How many ways can you select 3 sheriff deputies from 8 candidates? How many handshakes can occur between 5 people if everyone shakes hands? And can u also explain each one? i would be grateful and thank you! :D
anonymous
  • anonymous
deputies candidate: having 3 choosing from 8 so it's 8C3 = 8!/[3!*(8-3)! = 112
lilai3
  • lilai3
i'm sorry, i can't understand all dat... stuff
anonymous
  • anonymous
you need to choose 3 people from 8 candidates and 8C3 is the formula, the same formula with permutation
lilai3
  • lilai3
how did u get 112?
anonymous
  • anonymous
8C3 = 8!/[3!*(8-3)! = 8!/[3!*5! = (8*7*6*5*4*3*2*1) / [(3*2*1)*(5*4*3*2*1)] = 8*7*6 / 3*2 = 8*7 = 56, this is the correct answer
lilai3
  • lilai3
oh thank you and good night and then i'll be off.. with my personal stuff....... i'll sorta "contact" you if I'll need anymore help... ;)
anonymous
  • anonymous
ok, good night
lilai3
  • lilai3
waaaaaiiiiitttttt...... you forgot to explain the problem about the handshakes!!!!!
lilai3
  • lilai3
is it 3125? because then it's like 5*5*5*5*5...right?
anonymous
  • anonymous
we need to have 2 people to shake hand. So we need to choose 2 people from 5 people to have the hand shake. so 5C2 = 5!/[2!*(5-2)!] = 5!/(2!*3!) = 5*4*3*2*1 / [(2*1)*(3*2*1)] = 5*4 / 2 = 10
lilai3
  • lilai3
oh never mind i get it then thanks... so its: (5*4)/(2*1)=10 rite?
lilai3
  • lilai3
no answer? fne good night then

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