anonymous
  • anonymous
Fool's problem of the day, If \( 4x^2+12xy+by^2+6x+2fy-4=0 \) represents a pair of parallel lines, can you find the distance between them? Genre: Standard analytic geometry problem (Pair of straight lines) Rating: Easy (If you know how to do it)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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lgbasallote
  • lgbasallote
only fool and ishaan can understand one another tsk tsk @_@ hahaha
anonymous
  • anonymous
Hmm \[\frac{\sqrt{\frac{4f^2}{b^2} + \frac{16}{b}}}{1 + \frac{9}{f^2}}\]
anonymous
  • anonymous
Not accepted, from you Ishaan ;) ... are you sure we can't find the value of \( b \) and \( f \)? ;)

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anonymous
  • anonymous
Okay I will leave now, keep trying guys, I will post the solution the next time I come online :)
anonymous
  • anonymous
B = 9, F = 9/2 ?
anonymous
  • anonymous
Is that right?
anonymous
  • anonymous
Distance = 11/9? I am not sure though, I could be wrong, I had to derive the whole thing and made it complex than usual :/
anonymous
  • anonymous
Took me 20 minutes :/ nooooooo, my skills in Geometry are deteriorating :(
anonymous
  • anonymous
I did something wrong... Let me check it
anonymous
  • anonymous
\[\frac{\sqrt{\frac{4f^2}{b^2} + \frac{16}{b}}}{\sqrt {1 + \frac{9}{f^2}}}\]Distance = \(\frac{5}{3\sqrt{11}}\) \[\Huge \color{gray}{\text{_____________________________________}}\] Disgraceful :/
anonymous
  • anonymous
Just \(\frac{5}{\sqrt{11}}\), no three
anonymous
  • anonymous
I got \( \large \frac 5 {\sqrt{13}} \)
anonymous
  • anonymous
You got the correct value of f and g, :)
anonymous
  • anonymous
Yeah, 4+9 = 13, not 11.

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