anonymous
  • anonymous
Radius of curvature=35m, linear speed=10km/hr, find the angular velocity and acceleration. Please help me.
MIT 8.01 Physics I Classical Mechanics, Fall 1999
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SOLVED
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katieb
  • katieb
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Mani_Jha
  • Mani_Jha
Use \[v=wR\] Put v=10*5/18 m/s R=35
anonymous
  • anonymous
Can I use linear Speed=10km/hr=2.778m/s directly substitute in the formula a=v^2/R a=2.778^2/35=0.2208m/s^2. Is this correct?
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
Yes it is!

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anonymous
  • anonymous
\[\alpha=a/R \] alpha is the angular acceleration
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
@Natan In this example angular acceleration is zero. and (linear) acceleration is purely centripetal. If acceleration had a component tangent to the circle, then we would have: \(\large\alpha=\huge\frac{a_t}{R}\)
anonymous
  • anonymous
oh sorry !! is true it is a uniform circular motion thanks!

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