anonymous
  • anonymous
Is this right? The speed of a falling body varies directly with the time the body has fallen. If the speed of a falling body is 128ft per second at the end of the fourth second, what will be its speed at the end of the tenth second? Give me a sec and I'll write out my work. and can someone answer this? (let me draw it out too)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
lgbasallote
  • lgbasallote
oh my gosh physics O.O why dost thou behaunt me T_T
anonymous
  • anonymous
|dw:1332849844079:dw|
anonymous
  • anonymous
bc it's in my algebra lol

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lgbasallote
  • lgbasallote
why do girls have nice handwritings -___-
anonymous
  • anonymous
|dw:1332850035506:dw| sorryz for crappy writing
anonymous
  • anonymous
What does it mean that the speed of the falling body varies directly with the time the body has fallen? Does that mean it's linear or something? I don't do physics...
anonymous
  • anonymous
lol @lgb I just saw your post...and this is not nice I can't do it on the computer lol
anonymous
  • anonymous
It's a direct variation thing
lgbasallote
  • lgbasallote
better than us guys :P =))
anonymous
  • anonymous
v = k*t, v is the speed and t is the time with k being the proportionality constant. 128 = k*4 ...from the question itself. k = 32 It implies Velocity at the end of 10th second should be, v=32*10 = 320 feet per second. \[\Huge \text{______________________________________}\] Maybe, I am not so sure though :/
anonymous
  • anonymous
thanks ishaan94
anonymous
  • anonymous
:-)

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