anonymous
  • anonymous
Determine whether Rolle's theorm can be applied on the closed interval [a, b]. If Rolle's theorm can be applied, find all vales of c in the interval [a,b] such that f'(c)=0. If Rolle's theorm cannot be applied, explain why not.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
f(x)=(x-1)(x-2)(x-3), [1,3]
anonymous
  • anonymous
since \[f(1)=f(3)=0\] and since any polynomial is differentiable you can use rolle
anonymous
  • anonymous
\[f(x)=x^3-6 x^2+11 x-6\] \[f'(x)=3x^2-12x+11\] so rolle says there somewhere in [1,3] there is a number c with \[f'(c)=0\] set \[3x^2-12x+11=0\] solve for x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
that is where i am stuck, i got that far
anonymous
  • anonymous
use the quadratic formula if it does not factor
anonymous
  • anonymous
if that is too annoying, then cheat http://www.wolframalpha.com/input/?i=3x^2-12x%2B11%3D0
anonymous
  • anonymous
-b+-sqrt(b^2-4ac)/2a?
anonymous
  • anonymous
yup

Looking for something else?

Not the answer you are looking for? Search for more explanations.