anonymous
  • anonymous
An electric trimmer blade has rotational inertia 1.55×10−4 kg*m^2. What torque is needed to accelerate this blade from rest to 620 rpm in 1.35 s? How much work was done to accelerate the blade?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i already found the torque which is 7.45*10^-4 but i dont know how to find the second part which asks how much work was done to accelerate the blade
experimentX
  • experimentX
F = ma F = torque accn = find angular accn mass = inertia
anonymous
  • anonymous
Torque is 7.45*10^-4 N*m

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experimentX
  • experimentX
angular acceleration = ??
anonymous
  • anonymous
it doesn't say.. the question only says "How much work was done to accelerate the blade?" so i don't know if they want the angular acceleration
experimentX
  • experimentX
you must find it first ... else you can't find the torque
experimentX
  • experimentX
620 rpm = angular velocity = 620*2*pi/60 = how much is that??
anonymous
  • anonymous
64.93
experimentX
  • experimentX
now angular acceleration = (620*2*pi/60-0)/1.35 /s^2, now use this in the relation T = I*a where T is torque, and a is angular accn and I is Inertia
experimentX
  • experimentX
Jeez .... you surprise me ... finding torque without angular accn
anonymous
  • anonymous
\[\omega=620*2\pi =64.93 rad/\sec\] \[\alpha=\omega/t= 64.93/1.35= 48.09 rad/\sec^2\] \[\tau=I*\alpha= 1.55*10^-4*48.09= 7.45*10^-3 N.m\] this is how i found torque but i dont know how to find acceleration. what equation am i suppose to use?
experimentX
  • experimentX
alpha is your angular accn
experimentX
  • experimentX
that is exactly the equation you are supposed to use
anonymous
  • anonymous
ok thanks

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