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Confused?? O.o

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Someone help meee
\[\left( \sqrt[4]{6} \right)^{12x-4}=36^{x+4}\] Is this correct?

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yes thats it
I'll help you shortly.
okay thanks
  • phi
you do know \[\sqrt[4]{6}= 6^{\frac{1}{4}}\]
  • phi
you also know the general rule \[ (a^b)^c = a^{bc} \]
  • phi
so let's use both ideas. replace fourth root of 6 with 6^(1/4) \[ (6^{\frac{1}{4}})^{12x-4} = 6^{\frac{12x-4}{4} }\]
  • phi
can you simplify from here?
Yeah I think so, and it comes out to be x=9 correct?
  • phi
yes if we equate \[ 6^{3x-1} = 6^{2(x+4)} \] then the exponents must be equal 3x-1= 2x+8 x= 9

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