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Adam1994 Group TitleBest ResponseYou've already chosen the best response.0
dw:1332877354175:dw
 2 years ago

Adam1994 Group TitleBest ResponseYou've already chosen the best response.0
Someone help meee
 2 years ago

jagatuba Group TitleBest ResponseYou've already chosen the best response.0
\[\left( \sqrt[4]{6} \right)^{12x4}=36^{x+4}\] Is this correct?
 2 years ago

Adam1994 Group TitleBest ResponseYou've already chosen the best response.0
yes thats it
 2 years ago

jagatuba Group TitleBest ResponseYou've already chosen the best response.0
I'll help you shortly.
 2 years ago

Adam1994 Group TitleBest ResponseYou've already chosen the best response.0
okay thanks
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
you do know \[\sqrt[4]{6}= 6^{\frac{1}{4}}\]
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
you also know the general rule \[ (a^b)^c = a^{bc} \]
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
so let's use both ideas. replace fourth root of 6 with 6^(1/4) \[ (6^{\frac{1}{4}})^{12x4} = 6^{\frac{12x4}{4} }\]
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
can you simplify from here?
 2 years ago

Adam1994 Group TitleBest ResponseYou've already chosen the best response.0
Yeah I think so, and it comes out to be x=9 correct?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.2
yes if we equate \[ 6^{3x1} = 6^{2(x+4)} \] then the exponents must be equal 3x1= 2x+8 x= 9
 2 years ago
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