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Adam1994

Confused?? O.o

  • 2 years ago
  • 2 years ago

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  1. Adam1994
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    |dw:1332877354175:dw|

    • 2 years ago
  2. Adam1994
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    Someone help meee

    • 2 years ago
  3. jagatuba
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    \[\left( \sqrt[4]{6} \right)^{12x-4}=36^{x+4}\] Is this correct?

    • 2 years ago
  4. Adam1994
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    yes thats it

    • 2 years ago
  5. jagatuba
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    I'll help you shortly.

    • 2 years ago
  6. Adam1994
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    okay thanks

    • 2 years ago
  7. phi
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    you do know \[\sqrt[4]{6}= 6^{\frac{1}{4}}\]

    • 2 years ago
  8. phi
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    you also know the general rule \[ (a^b)^c = a^{bc} \]

    • 2 years ago
  9. phi
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    so let's use both ideas. replace fourth root of 6 with 6^(1/4) \[ (6^{\frac{1}{4}})^{12x-4} = 6^{\frac{12x-4}{4} }\]

    • 2 years ago
  10. phi
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    can you simplify from here?

    • 2 years ago
  11. Adam1994
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    Yeah I think so, and it comes out to be x=9 correct?

    • 2 years ago
  12. phi
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    yes if we equate \[ 6^{3x-1} = 6^{2(x+4)} \] then the exponents must be equal 3x-1= 2x+8 x= 9

    • 2 years ago
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