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Adam1994
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dw:1332877354175:dw

Adam1994
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Someone help meee

jagatuba
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\[\left( \sqrt[4]{6} \right)^{12x4}=36^{x+4}\] Is this correct?

Adam1994
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yes thats it

jagatuba
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I'll help you shortly.

Adam1994
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okay thanks

phi
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you do know
\[\sqrt[4]{6}= 6^{\frac{1}{4}}\]

phi
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you also know the general rule
\[ (a^b)^c = a^{bc} \]

phi
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so let's use both ideas. replace fourth root of 6 with 6^(1/4)
\[ (6^{\frac{1}{4}})^{12x4} = 6^{\frac{12x4}{4} }\]

phi
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can you simplify from here?

Adam1994
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Yeah I think so, and it comes out to be x=9 correct?

phi
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yes if we equate
\[ 6^{3x1} = 6^{2(x+4)} \]
then the exponents must be equal
3x1= 2x+8
x= 9