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Adam1994
 3 years ago
Confused?? O.o
Adam1994
 3 years ago
Confused?? O.o

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jagatuba
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( \sqrt[4]{6} \right)^{12x4}=36^{x+4}\] Is this correct?

jagatuba
 3 years ago
Best ResponseYou've already chosen the best response.0I'll help you shortly.

phi
 3 years ago
Best ResponseYou've already chosen the best response.2you do know \[\sqrt[4]{6}= 6^{\frac{1}{4}}\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.2you also know the general rule \[ (a^b)^c = a^{bc} \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.2so let's use both ideas. replace fourth root of 6 with 6^(1/4) \[ (6^{\frac{1}{4}})^{12x4} = 6^{\frac{12x4}{4} }\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.2can you simplify from here?

Adam1994
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I think so, and it comes out to be x=9 correct?

phi
 3 years ago
Best ResponseYou've already chosen the best response.2yes if we equate \[ 6^{3x1} = 6^{2(x+4)} \] then the exponents must be equal 3x1= 2x+8 x= 9
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