anonymous
  • anonymous
Confused?? O.o
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
Someone help meee
jagatuba
  • jagatuba
\[\left( \sqrt[4]{6} \right)^{12x-4}=36^{x+4}\] Is this correct?

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anonymous
  • anonymous
yes thats it
jagatuba
  • jagatuba
I'll help you shortly.
anonymous
  • anonymous
okay thanks
phi
  • phi
you do know \[\sqrt[4]{6}= 6^{\frac{1}{4}}\]
phi
  • phi
you also know the general rule \[ (a^b)^c = a^{bc} \]
phi
  • phi
so let's use both ideas. replace fourth root of 6 with 6^(1/4) \[ (6^{\frac{1}{4}})^{12x-4} = 6^{\frac{12x-4}{4} }\]
phi
  • phi
can you simplify from here?
anonymous
  • anonymous
Yeah I think so, and it comes out to be x=9 correct?
phi
  • phi
yes if we equate \[ 6^{3x-1} = 6^{2(x+4)} \] then the exponents must be equal 3x-1= 2x+8 x= 9

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