## Adam1994 3 years ago Confused?? O.o

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Someone help meee

3. jagatuba

$\left( \sqrt[4]{6} \right)^{12x-4}=36^{x+4}$ Is this correct?

yes thats it

5. jagatuba

okay thanks

7. phi

you do know $\sqrt[4]{6}= 6^{\frac{1}{4}}$

8. phi

you also know the general rule $(a^b)^c = a^{bc}$

9. phi

so let's use both ideas. replace fourth root of 6 with 6^(1/4) $(6^{\frac{1}{4}})^{12x-4} = 6^{\frac{12x-4}{4} }$

10. phi

can you simplify from here?

Yeah I think so, and it comes out to be x=9 correct?

12. phi

yes if we equate $6^{3x-1} = 6^{2(x+4)}$ then the exponents must be equal 3x-1= 2x+8 x= 9