anonymous
  • anonymous
what is the x intercepts of f(x)=x^2+2 please provide steps if possible, thank you very much
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
x intercept is where the graph crosses the x-axis, and that is where y = 0, right?
anonymous
  • anonymous
i'm not sure :/ all i did was used the quadratic formula but i'm getting a negative under the square root
anonymous
  • anonymous
yes, the answers are imaginary

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anonymous
  • anonymous
so there are no x intercepts
anonymous
  • anonymous
on a graph the x intercept is will shape the parabola while the vertex = (0,2)
anonymous
  • anonymous
not really... but if you have a good imagination, you can say that \[i \sqrt{2} , -i \sqrt{2}\] are where it crosses
anonymous
  • anonymous
can you show me how did you did you do that?
anonymous
  • anonymous
no, you will hit imaginary numbers later... i is the square root of -1 just show the work you did to show that the parabola doesn't cross the axis
anonymous
  • anonymous
there are no real roots, only imaginary ones
anonymous
  • anonymous
im not sure how to draw this parabola its suppose to look like this|dw:1332883453715:dw|
anonymous
  • anonymous
if you have not worked with imaginary numbers yet, just stop at the negative square root and say it is impossible. You are right. And yes, the parabola is centered on the axis and slid up two units.
anonymous
  • anonymous
yeah but the problem is how would i draw that if there's 11 units from the center to the top? i dont know far wide to draw it
anonymous
  • anonymous
that's where you plot points (or a graphing calculator)
anonymous
  • anonymous
you are better at this than you think... trust your instincts

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