Consider the line -5x+3y=1 Find the equation of the line that is parallel to this line and passes through the point (1,-4)

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Consider the line -5x+3y=1 Find the equation of the line that is parallel to this line and passes through the point (1,-4)

Mathematics
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for any two lines that are parallel, their slopes will be same, but the value of the y-intercept will be different. |dw:1332884638617:dw| so basically you can say that if a line is ax+by+c=0, the parallel twin will be ax+by+k=0 now for solving the question, just write the new line as ax+by+k=0 and put the value (x,y) in it form the coordinates of the point through which the line passes, and get the value of 'k' now put 'k' in the equation that is, ax+by+k=0 (where a and b are known of course), and you have your answer staring right in your face!! solve and post the answer that you get to verify!!
as the slopes of line are equal only constants will be varyin....so now find the slope which comes out to be 5/3 and as you know the slope now substitute in the equation Y-y=slope{X-x}....wher x n y are the given points.....you get the ans as -5x+3y+9=0 and thats it....

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