anonymous
  • anonymous
How do you find the zeros of f(x)= x^3+11x^2-150x-1512; -4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
they are telling you that x+4 is a factor? so you can divide by x+4 using long division or -4 using synthetic division and solve the quadratic quotient
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
with synthetic divison I got -2562 as the answer???

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anonymous
  • anonymous
you should get a quotient in the form of ax^2+bx+c, not a single constant
anonymous
  • anonymous
what is that -4 after f(x)? -4 is not a zero to f(x) so why is it listed in the problem?
anonymous
  • anonymous
The directions say "Given one zero of the polynomial function, find the other zeros"
anonymous
  • anonymous
yes, but -4 is not a zero of f(x) in your problem...did you type it correctly in here?
anonymous
  • anonymous
yes, thats how it was given in the book, thats what I was unsure of...
anonymous
  • anonymous
maybe its a typo. you can graph it on your calculator and find the zeros if you want, or you can use descartes rule of signs and the rational zeros theorem, but there are a huge number of factors of 1512 for trial and error
anonymous
  • anonymous
I don't know whats up with that because there are ten problems in the book like those I typed...but thanks i'll try try putting it in my calculator.
anonymous
  • anonymous
one zero is -14, i'll give you that.
asnaseer
  • asnaseer
Dockworker is right - this is definitely a typo, -14 is one root of this polynomial
anonymous
  • anonymous
okay

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