anonymous
  • anonymous
How much heat is required to raise the temperature of 210g OF CH3OH(l) from 22.0 to 30.0deg C and then vaporize it at 30.0C? Use molar heat capacity of CH3OH(l) of 81.1 J: mol^-1 K^-1.
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
we use our handy dandy q = (mas)(Csp)(deltaT) where Csp is molar heat capacity and delta T change in temp(final - initial) we just plug and chug. \[q= (CH _{3}OHmoles)(81.1J/molK)(30.0K-22.0K) \] The only hard part is converting the ch3oh into moles. :) I don't know what you mean vaporize it at 30.0C That doesn't make sense. Are you asking if it is a vapor at that temp?

Looking for something else?

Not the answer you are looking for? Search for more explanations.