## IsTim 3 years ago Given each scalar equation, write a vector equation. x=8

1. IsTim

I was thinking that the normal vector was [8,0] and that the direction vector was [0,-8] and the position vector was [8,0].

2. IsTim

I was wrong.

3. IsTim

My final answer was [x,y]=[8,0]+t[0,-8]. But I am wrong.

4. IsTim

MYsesshou, are you my savior in this dark time?

5. IsTim

Assassin, are you able to assist me?

6. mysesshou

Actually, I'm not quite sure. Sorry !! Sorry for lag. I have been fighting my computer and this site for like an hour.

7. IsTim

I think everyone has. Ok. Oh well.

8. mysesshou

was that the only info you're given?

9. IsTim

Yes. Alongside the info in the textbook explaining how to do this.

10. mysesshou

I'm still searching, but can you apply something like this? http://www.blurtit.com/q1900770.html (google'd) I don't have your book... is it a calc book?

11. IsTim

I dunno. Yes, it is a Calculus and Vectors book.

12. IsTim

Are you able to help?

13. mysesshou

Probably not, but I've been searching

14. IsTim

I'll rally up others just in case.

15. mysesshou

Sorry, it's just been too long for me for this to be recalled.

16. IsTim

Yeah. Happened to me when I was helping someone else on inequalities.

17. IsTim

@Zarkon Uh, someone told me to ask you.

18. PaxPolaris

19. IsTim

20. IsTim

Any clue?

21. IsTim

I've double-checked to make sure the facts are right.

22. PaxPolaris

the -8 isn't necessary but acceptable.... both your eq. and answer equation are acceptable...

23. PaxPolaris

direction vector can be any vertical vector... starting point postion vector can refer to any point on line Infinite acceptable answers.

24. IsTim

Like, I know that [8,0] can be anything, but my answer still isn't right in terms of t[0,1].

25. mysesshou

Sorry IsTim, I've searched through my calc book and solutions manual, but I guess 8-9 years is too long to remember enough of this. Hope PaxPolaris is able to help you understand. :)

26. PaxPolaris

direction vector can be any vertical vector ... [0,1] and [0,-8] are both parallel to the line so both are acceptable ... any vector [0,C] is acceptable.

27. IsTim

Wait, you're sure you're not talking about position vector?

28. PaxPolaris

no, we're done with that...??

29. IsTim

I don't know, they way you describe the direction vector sounds like the way my teacher described a position vector.

30. PaxPolaris

Position Vector: of any 1 point on the line Direction Vector: any vector parallel to the line

31. IsTim

But then what's the constant?

32. PaxPolaris

the slope of the direction vector is constant ... the length of the direction vector is irrelevant

33. IsTim

Ok. I'll just leave this question as is for now. Thanks for the help anyways, PAx.

34. PaxPolaris

eg. if your direction vector is [1,2]: it can also be [2,4] , [3,6], [-5,-10]....[n,2n] preferably you'd use the simplest form i.e. [1,2] or in your case [0,1] instead of [0,-8] http://www.netcomuk.co.uk/~jenolive/vect3.html

35. IsTim

Hey Sess, I'm good now. Thanks for staying though. I'll take a look at it Pax Polaris.

36. mysesshou

Evidently, my book wasn't good enough to help. I was reading through some of this, after p.4, that seemed that it might help some. http://mysite.science.uottawa.ca/vbozi013/mat1339/ch08.pdf PaxPolaris' site is good too :)

37. mysesshou

Yay PaxPolaris for the help !

38. amistre64

i think i missed the original problem as stated