A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I was thinking that the normal vector was [8,0] and that the direction vector was [0,8] and the position vector was [8,0].

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1My final answer was [x,y]=[8,0]+t[0,8]. But I am wrong.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1MYsesshou, are you my savior in this dark time?

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Assassin, are you able to assist me?

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Actually, I'm not quite sure. Sorry !! Sorry for lag. I have been fighting my computer and this site for like an hour.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I think everyone has. Ok. Oh well.

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0was that the only info you're given?

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Yes. Alongside the info in the textbook explaining how to do this.

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0I'm still searching, but can you apply something like this? http://www.blurtit.com/q1900770.html (google'd) I don't have your book... is it a calc book?

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I dunno. Yes, it is a Calculus and Vectors book.

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Probably not, but I've been searching

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I'll rally up others just in case.

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry, it's just been too long for me for this to be recalled.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Yeah. Happened to me when I was helping someone else on inequalities.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1@Zarkon Uh, someone told me to ask you.

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2why is your answer wrong?

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1The actual answer is [x,y]=[8,2]+t[0,1].

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I've doublechecked to make sure the facts are right.

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2the 8 isn't necessary but acceptable.... both your eq. and answer equation are acceptable...

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2direction vector can be any vertical vector... starting point postion vector can refer to any point on line Infinite acceptable answers.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Like, I know that [8,0] can be anything, but my answer still isn't right in terms of t[0,1].

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry IsTim, I've searched through my calc book and solutions manual, but I guess 89 years is too long to remember enough of this. Hope PaxPolaris is able to help you understand. :)

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2direction vector can be any vertical vector ... [0,1] and [0,8] are both parallel to the line so both are acceptable ... any vector [0,C] is acceptable.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Wait, you're sure you're not talking about position vector?

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2no, we're done with that...??

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1I don't know, they way you describe the direction vector sounds like the way my teacher described a position vector.

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2Position Vector: of any 1 point on the line Direction Vector: any vector parallel to the line

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1But then what's the constant?

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2the slope of the direction vector is constant ... the length of the direction vector is irrelevant

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Ok. I'll just leave this question as is for now. Thanks for the help anyways, PAx.

PaxPolaris
 2 years ago
Best ResponseYou've already chosen the best response.2eg. if your direction vector is [1,2]: it can also be [2,4] , [3,6], [5,10]....[n,2n] preferably you'd use the simplest form i.e. [1,2] or in your case [0,1] instead of [0,8] http://www.netcomuk.co.uk/~jenolive/vect3.html

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.1Hey Sess, I'm good now. Thanks for staying though. I'll take a look at it Pax Polaris.

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Evidently, my book wasn't good enough to help. I was reading through some of this, after p.4, that seemed that it might help some. http://mysite.science.uottawa.ca/vbozi013/mat1339/ch08.pdf PaxPolaris' site is good too :)

mysesshou
 2 years ago
Best ResponseYou've already chosen the best response.0Yay PaxPolaris for the help !

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0i think i missed the original problem as stated
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.