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I was wrong.

My final answer was [x,y]=[8,0]+t[0,-8]. But I am wrong.

MYsesshou, are you my savior in this dark time?

Assassin, are you able to assist me?

I think everyone has. Ok. Oh well.

was that the only info you're given?

Yes.
Alongside the info in the textbook explaining how to do this.

I dunno.
Yes, it is a Calculus and Vectors book.

Are you able to help?

Probably not, but I've been searching

I'll rally up others just in case.

Sorry, it's just been too long for me for this to be recalled.

Yeah. Happened to me when I was helping someone else on inequalities.

why is your answer wrong?

The actual answer is [x,y]=[8,2]+t[0,1].

Any clue?

I've double-checked to make sure the facts are right.

the -8 isn't necessary but acceptable.... both your eq. and answer equation are acceptable...

Like, I know that [8,0] can be anything, but my answer still isn't right in terms of t[0,1].

Wait, you're sure you're not talking about position vector?

no, we're done with that...??

Position Vector: of any 1 point on the line
Direction Vector: any vector parallel to the line

But then what's the constant?

the slope of the direction vector is constant ... the length of the direction vector is irrelevant

Ok. I'll just leave this question as is for now. Thanks for the help anyways, PAx.

Hey Sess, I'm good now. Thanks for staying though.
I'll take a look at it Pax Polaris.

Yay PaxPolaris for the help !

i think i missed the original problem as stated