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anonymous
 4 years ago
Find the center and the radius of the circle with the given equation.
Problem 1) x^2+y^2+9x8y+4=0
Problem 2) x^2+y^26y=0
anonymous
 4 years ago
Find the center and the radius of the circle with the given equation. Problem 1) x^2+y^2+9x8y+4=0 Problem 2) x^2+y^26y=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok we want to put the circles into standard form: (x  a)^2 + (y  b)^2 = r^2 where the center is (a,b) and the radius is r so for #1: x^2 + y^2 + 9x  8y + 4 = 0 x^2 + 9x + y^2  8y = 4 we complete the square for x,y: x^2 + 9x + 81/4 + y^2  8y + 16 = 4 + 81/4 + 16 = 161/4 (x + 9/2)^2 + (y  4)^2 = 161/4 so (a,b) = (9/2, 4) and r = sqrt(161/4) = sqrt(161)/2 for #2: x^2+y^26y=0 x^2 + y^2  6y + 9 = 9 x^2 + (y  3)^2 = 9 so (a,b) = (0,3) and r = sqrt(9) = 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0err for #1 i meant x^2 + 9x + y^2  8y = 4 so r^2 = 4 + 81/4 + 16 = 81/4 + 12 = 129/4 meaning r = sqrt(129)/2
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