anonymous
  • anonymous
Find the center and the radius of the circle with the given equation. Problem 1) x^2+y^2+9x-8y+4=0 Problem 2) x^2+y^2-6y=0
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
ok we want to put the circles into standard form: (x - a)^2 + (y - b)^2 = r^2 where the center is (a,b) and the radius is r so for #1: x^2 + y^2 + 9x - 8y + 4 = 0 x^2 + 9x + y^2 - 8y = 4 we complete the square for x,y: x^2 + 9x + 81/4 + y^2 - 8y + 16 = 4 + 81/4 + 16 = 161/4 (x + 9/2)^2 + (y - 4)^2 = 161/4 so (a,b) = (9/2, 4) and r = sqrt(161/4) = sqrt(161)/2 for #2: x^2+y^2-6y=0 x^2 + y^2 - 6y + 9 = 9 x^2 + (y - 3)^2 = 9 so (a,b) = (0,3) and r = sqrt(9) = 3
anonymous
  • anonymous
err for #1 i meant x^2 + 9x + y^2 - 8y = -4 so r^2 = -4 + 81/4 + 16 = 81/4 + 12 = 129/4 meaning r = sqrt(129)/2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.