anonymous
  • anonymous
Which value(s) of x should be excluded for the polynomial? x^2-16/x^2-6x+9 A. 3 B. 3 and -3 C. 4 D. 4 and -4
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I think it's D
IsTim
  • IsTim
Why excluded?
anonymous
  • anonymous
wat do u mean?

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IsTim
  • IsTim
Actually, just ignore me. Someone else, help!
anonymous
  • anonymous
you can never divide by 0 so where will there be a problem with this one?
anonymous
  • anonymous
it's A- (3)
anonymous
  • anonymous
because???
anonymous
  • anonymous
ik how did u get tht?
anonymous
  • anonymous
he is wrong, by the way
anonymous
  • anonymous
okay so then wat is it philip
anonymous
  • anonymous
you cannot divide by zero, so what values for x will cause problems here? that is the question
anonymous
  • anonymous
what is the denominator? and when is it 0?
anonymous
  • anonymous
sorry, forgot to ask, do you want to learn this stuff or just want to fill in some homework? I am ok with it either way.
anonymous
  • anonymous
look Factorize them (x^2-16)/(x^2-6x+9) so (x^2-16) = (x-4)(x+4) (x^2-6x+9)=(X-3)(x-3) therefore (x-4)(x+4)/(x-3)(x-3) since any denominator makes the whole equation undefined Therefore the no. 3 is Refused i mean Answer (A)
anonymous
  • anonymous
fill in sum homework but kind of want to know a little about it.
anonymous
  • anonymous
i mean when the denominator=0 the whole equation is undefined
anonymous
  • anonymous
yep, that's right. I was mistaken. appologies where appropriate
anonymous
  • anonymous
okay thnk u jop and philip u guys helped aa lot

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