anonymous
  • anonymous
Algebra 2 help please!! 1. What is the simplified form of (x-3)/(x^2+x-12)• (x+4)/(x^2+8x+16) ? 2.What is the simplified form of (x+1)/(x^2+x-6) divided by (x^2+5x+4)/(x+3)? 3.What is the simplified form of (y)/(y^2-x^2) – (x)/(y^2-x^2) ? 4. What is the simplified form of (2)/(x^2-x) - (1)/(x) ? Answers I got: 1. (1)/(x+4)^2 2.(1)/(x-2)(x+4) 3.(1)/(x-y) 4.(1-x)/(x(x-1)) Thanks!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1. - Correct
anonymous
  • anonymous
2. - Correct
anonymous
  • anonymous
3. I got: y/(y+x)(y-x) - x/(y+x)(y-x) = (y-x)/((y+x)(y-x)) = 1/(y+x)

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anonymous
  • anonymous
Thanks so muich for all of the help!! You rock!
anonymous
  • anonymous
4. For this one, I got: 2/x(x-1) - (x-1)/x(x-1) = (2-(x-1))/(x(x-1)) = (3-x)/(x(x-1))
anonymous
  • anonymous
You couldn't possibly tell me how to simplify this too could you?? (3)/(2x-5) + (21)(8x^2-14x-15) Thanks again!
anonymous
  • anonymous
I'll give it a shot :-)
anonymous
  • anonymous
Awesome!
anonymous
  • anonymous
That second one is going to be 21 over (2x+5)(4x-3). I just did it by trial and error. Wanna try solving from there and we'll compare?
anonymous
  • anonymous
Okay sounds good!
anonymous
  • anonymous
3(4x-3)/((2x+5)(4x-3)) + 21/((2x+5)(4x-3)) = (3(4x-3) +21)/((2x+5)(4x-3))
anonymous
  • anonymous
I think the final answer would be 6(x+1)/(2x+5)(4x+3)
anonymous
  • anonymous
I got (12(x+1))/((2x+5)(4x-3))
anonymous
  • anonymous
Okay, thanks so much!
anonymous
  • anonymous
Oh CRAP! I treated it like +14 in the polynomial
anonymous
  • anonymous
If you would like to go off and work on another problem, I'll resolve it for you.
anonymous
  • anonymous
Okay, thanks :)
anonymous
  • anonymous
= 3/(2x+5) + 21/((2x-5)(4x+3)) =(3(2x-5)(4x+3))/((2x+5)(2x-5)(4x+3)) + (21(2x+5))/((2x+5)(2x-5)(4x+3)) =(3(2x-5)(4x+3) + 21(2x+5))/((2x+5)(2x-5)(4x+3)) = ((6x-15)(4x+3) +42x +105)/((2x+5)(2x-5)(4x+3)) = (24x^2 -42 +42 +105)/((2x+5)(2x-5)(4x+3)) = (24x^2 +105)/((2x+5)(2x-5)(4x+3)) Pretty lengthy, I know :-(
anonymous
  • anonymous
Wow! Thanks so much!! You wouldn't happen to know how to solve fractions inside fractions would you?
anonymous
  • anonymous
from inside out?
anonymous
  • anonymous
Ya, I am trying that, do you want to give it a go as well of would you rather not?
anonymous
  • anonymous
sure I'll look at this last one.
anonymous
  • anonymous
Cool, thanks! what is the simplified form of (15xy^2)/(x^2+5x+6) over (15xy^2)/(x+2)(x+3)
anonymous
  • anonymous
So I'll ask you this. If you have \[a/b \div c/d\] What would you do to re-write it?
anonymous
  • anonymous
Change it to multiplication and flip the second fraction, would this one be the same though because of the fraction as a numerator and a fraction as the denominator?
anonymous
  • anonymous
Yup. So you have a/b * d/c
anonymous
  • anonymous
sec, I'll re-write what you have to give you a hint...
anonymous
  • anonymous
I wrote the wrong equation, it should be: what is the simplified form of (15xy^2)/(x^2+5x+6) over (5x^2y)/(2x^2+7x+3) Sorry!!
anonymous
  • anonymous
\[(15xy ^{2})/(x ^{2}+5x+16) \div (15xy ^{2})/((x+2)(x+3)\]
anonymous
  • anonymous
So if you flip the right fraction, you'll be able to cancel out 15xy^2.
anonymous
  • anonymous
Oh, it's 6 on the bottom, not 16. Sorry about that.
anonymous
  • anonymous
I wrote the equation wrong the first time, read the post right before you finished writing it all out. Sorry
anonymous
  • anonymous
oh okay one sec.
anonymous
  • anonymous
Do you know how to factor this? x^2+5x+6
anonymous
  • anonymous
Yes, I got (x+2)(x+3) but I do not know how to factor 2x^2+7x+3
anonymous
  • anonymous
Hmm... I don't think it's factor-able.
anonymous
  • anonymous
\[(15xy^2)/((x+2)(x+3)) \div (5x^2y)/(2x^2+7x+3)\]
anonymous
  • anonymous
It's not factorable, but that doesn't matter. What do you do to re-write this?
anonymous
  • anonymous
Multiply and flip the last fraction, that is where I got stuck
anonymous
  • anonymous
K, that's fine. I just wanted to make sure you were at that step.
anonymous
  • anonymous
Yep :)
anonymous
  • anonymous
For the final answer, I ended up with: (3y *(2x^2+7x+3))/((x+2)(x+3)*x)
anonymous
  • anonymous
The 15xy^2/5x^2y becamse 3y/x
anonymous
  • anonymous
Alrighty, thanks for the help
anonymous
  • anonymous
Some of these get pretty messy!
anonymous
  • anonymous
Yeah, they do!
anonymous
  • anonymous
If you can really learn all of this basic stuff, you are going to THANK yourself when you get into calculus.
anonymous
  • anonymous
You got that right!!!

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