anonymous
  • anonymous
HIII/HELP who can help with both or one of these precalc questions my last two!!!!**
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
First one, if 5cos(x) =5/2, then cos(x)=1/2. Can't remember my trigonometric circle by heart, but I bet you have that lying around somewhere on your desk

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So cos x = 1/2 which indicates x= pi/3, 5pi/3, 7pi/3, or 11pi/3
anonymous
  • anonymous
Remember that cos x = 1/2 comes from a 30/60/90 triangle.
anonymous
  • anonymous
\[\sqrt{\csc^2(\theta)-1}=\sqrt{\frac{1}{\sin^2(\theta)}-1}=\sqrt{\frac{1-\sin^2(\theta)}{\sin^2(\theta)}}=\sqrt{\cot^2(\theta)}=\cot(\theta)\]
anonymous
  • anonymous
how does x= pi/3, 5pi/3, 7pi/3, the same thing as=== 11pi/3?
anonymous
  • anonymous
and so what is the answer for the second one out of all of that? animalain!?
anonymous
  • anonymous
there are 2 values between 0 and 2pi where cos(x) = 1/2, pi/3 and 5pi/3. To find the values for 2pi to 4pi, you just add 2pi to those first values
anonymous
  • anonymous
pi/3 is in quadrant one; 5pi/3 is in quadrant four. 7pi/3 and 11pi/3 are on the second lap, since we are going for theta in [0,4pi]
anonymous
  • anonymous
soo the final answer!? im still confused im gonna have to go to tutoring tomorrow but so x=?
anonymous
  • anonymous
The problem goes from left to right. The answer is on the right.
anonymous
  • anonymous
what does it mean when it says (Enter the argument of the trigonometric function in parentheses.) is that the theta sign
anonymous
  • anonymous
Steps for my solution of problem two above: 1. Problem statement. 2. Substitute definition of csc. 3. Rephrase argument of radical as single rational expression. 4. 1- sin^2 = cos^2 then argument is cot^2 5. Square root of cot^2 is cot.
anonymous
  • anonymous
The argument is the value or expression you put into the function, radical, absolute value, etc.
anonymous
  • anonymous
cot(theta) wasnt right :(
anonymous
  • anonymous
= - cot(theta)
anonymous
  • anonymous
Good catch. The function is negative in the second quadrant, and the answer is positive, so we need the negative sign to make it all play nice.

Looking for something else?

Not the answer you are looking for? Search for more explanations.