anonymous
  • anonymous
Find all zeros of the polynomial. P(x) = x^5 - 29x^3 - 58x^2 + x - 29.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
this is written correctly? there are no rational roots to help simplify it
anonymous
  • anonymous
Right, it can be divided with synthetic division by 29
PaxPolaris
  • PaxPolaris
remainder won't be 0

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anonymous
  • anonymous
then factored by (x^2+1)^2, bit it needs to be reduced further
anonymous
  • anonymous
as pax said, 29 isn't a zero
anonymous
  • anonymous
unless you made a typo
anonymous
  • anonymous
i reconstructed the original with your quotient, yes...i got that
anonymous
  • anonymous
x^5-29x^4+2x^3-58x^2+x-29
anonymous
  • anonymous
so x^2+1=0 x^2=-1 x= +/- i, i multiplicity 2, -i multiplicity 2, 29 are the zeros
anonymous
  • anonymous
awesome! thats what i got.

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