anonymous
  • anonymous
The number of real roots of (x+3)^4 + (x+5)^4 = 16 is: a) 0 b) 2 c) 4 d) none of these
IIT study group
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
2
King
  • King
hw?
anonymous
  • anonymous
homework

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King
  • King
how?
anonymous
  • anonymous
-3 and -5 I did inspection that's all I did, but you should expand it if you can
King
  • King
what do u mean by u did inspection?
anonymous
  • anonymous
you can't do it, not now, maybe when you will have enough experience then... but for now just expand it
anonymous
  • anonymous
(x + 3)^4 = 4^2 - ((x +5)^2)^2 now try it
King
  • King
ok
anonymous
  • anonymous
That's rite, even I did it by seeing it in first glimpse. It is a DPP question of Vidyamandir Classes, NewDelhi. Is der any formula for finding the direct roots of a quartic equation?
AravindG
  • AravindG
hmm surprising i think i saw this qn before wait,,
anonymous
  • anonymous
Really? Then please answer something. Please.
AravindG
  • AravindG
w8
anonymous
  • anonymous
Okay bhai!!!!!!
AravindG
  • AravindG
hey i got it aadarsh!!!
anonymous
  • anonymous
I had posted the same question in maths group also. Got the answers.
King
  • King
the formula fr findin roots of a quadratic equation is \[\frac\]
King
  • King
\[\frac{-b \ \pm \sqrt{b ^{2}-4ac}}{2a}\]
anonymous
  • anonymous
\[(x+3)^4 + (x + 5)^4 = 16 \]\[x + 3 = t \tag1\]From (1), \[t^4 + (t+2)^4 = 16\]\[t^4 + (t+2)^4 = 2^4\]One can easily make out the equation is valid only when t is either 0 or -2.\[t = -2,0\]From (1), \(x = -5,-3\).

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