anonymous
  • anonymous
the spin only magnetic moment value in (bohr magneton units) of Cr(CO)6 is?
Chemistry
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
the no of unpaired electron=0, then themagnetic moment=sqrt(n(n+1))=0 |dw:1332925467432:dw|
anonymous
  • anonymous
i dont get the solution can anyone xplain me plzz
anonymous
  • anonymous
due to strong field ligand(CO), electrons are pushed to pair up.. as explained by VBT.

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anonymous
  • anonymous
ok ok i get it thnx :)
anonymous
  • anonymous
@prakharj the formula is M=sqrt(n(n+2))..sorry for this ok but here n=0 so the answer is correct..
anonymous
  • anonymous
no i had got that.., i was confused if i should pair up the only single electron in s or remaining electrons in d also.. thanx

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