mak_12 Group Title In △JKL, what is the length of KL? 2 years ago 2 years ago

1. mak_12 Group Title

2. No-data Group Title

$\cos 60 = \frac{23}{KL}$

3. mak_12 Group Title

$23\sqrt{2}$ $23\sqrt{3}$ 11.5 46

4. No-data Group Title

Solving for KL $KL = 46$

5. Directrix Group Title

KL = √3 * (KJ) = 23√3. --> answer This is because KL is the 60 leg in a 30-60-90 triangle with 30 leg 23. According to the theorem, the 60 leg is √3 times the 30 leg.