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mak_12 Group Title

In △JKL, what is the length of KL?

  • 2 years ago
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    \[\cos 60 = \frac{23}{KL}\]

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    \[23\sqrt{2}\] \[23\sqrt{3}\] 11.5 46

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    Solving for KL \[KL = 46\]

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    KL = √3 * (KJ) = 23√3. --> answer This is because KL is the 60 leg in a 30-60-90 triangle with 30 leg 23. According to the theorem, the 60 leg is √3 times the 30 leg.

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