By what number less than 2 must be multiplied so that the last 3 figures on the right end of the product may be 791

- King

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- schrodinger

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- King

igs hellp man....atleast try

- King

@JamesJ ,@Tomas.A ,@Diyadiya help guys help!!!

- King

help callisto!

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## More answers

- King

this frm real numbers chapter

- lgbasallote

oh man...im weak with these things @_@

- King

@Callisto u are the only one with a chance of doin this...so do u know how to do it?

- Callisto

Sorry i don't even understand the question :(
what number less than 2 <-- does it mean a single number?

- King

yeah there is some number...its related to HCF AND LCM THROUGH EUCLID'S DIVISION LEMMA

- Callisto

Sorry haven't learnt that :(

- anonymous

Word it right, you worded it so complex.

- King

its a problem in my phase-4 fiitjee package..i gave it to u the way it is worded

- King

but i dont understand answer is 871

- King

oh sry wait its by what number less than 2must be multiplied with 43521.....

- King

i by mistake frgt to mention 43521....:/

- anonymous

Oh

- King

so?

- anonymous

Let x be the number,
(435*100,000 + 521)*x = adasd...fsh791
So, last digit of x must be 1.
The answer is clearly 871, but I did this problem with logic and it's really tough to explain logic unless your communication skills are really impressive.
So... I am gonna tag @FoolForMath and @Mr.Math to see if they know some trick or the method you mentioned above.

- anonymous

btw basic multiplication is what I used.

- King

its 43521

- King

not 43500521

- anonymous

(435*1000 + 521)*x = adasd...fsh791

- anonymous

My bad

- King

its 43*1000 +521 or 435*100+21 rite?

- King

435*1000 + 521)=435521

- anonymous

yeah, again my bad :/

- King

oh and u can use any method......

- anonymous

but it doesn't matter, just get the 521 separately and then multiply it my x (the assumed number).|dw:1332944499486:dw|

- anonymous

by* not my ...and sorry for the bad handwriting.

- anonymous

871 is the answer, if you know the one line multiplication then this problem is a 10 seconder ;)

- King

@Ishaan94 what hav u done in the diagram can u post a normal reply the diagram is very messy so i cant understand anythin..................

- anonymous

http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG
I already told you, it's hard to explain. I don't wanna word it out.

- anonymous

@King , see my answer below. Hope u understand.

- anonymous

Please check the attached document. Hope u r clear now.

##### 1 Attachment

- King

Thnx @Aadarsh!!

- anonymous

Most welcome.

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