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King

  • 3 years ago

By what number less than 2 must be multiplied so that the last 3 figures on the right end of the product may be 791

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  1. King
    • 3 years ago
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    igs hellp man....atleast try

  2. King
    • 3 years ago
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    @JamesJ ,@Tomas.A ,@Diyadiya help guys help!!!

  3. King
    • 3 years ago
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    help callisto!

  4. King
    • 3 years ago
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    this frm real numbers chapter

  5. lgbasallote
    • 3 years ago
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    oh man...im weak with these things @_@

  6. King
    • 3 years ago
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    @Callisto u are the only one with a chance of doin this...so do u know how to do it?

  7. Callisto
    • 3 years ago
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    Sorry i don't even understand the question :( what number less than 2 <-- does it mean a single number?

  8. King
    • 3 years ago
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    yeah there is some number...its related to HCF AND LCM THROUGH EUCLID'S DIVISION LEMMA

  9. Callisto
    • 3 years ago
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    Sorry haven't learnt that :(

  10. Ishaan94
    • 3 years ago
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    Word it right, you worded it so complex.

  11. King
    • 3 years ago
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    its a problem in my phase-4 fiitjee package..i gave it to u the way it is worded

  12. King
    • 3 years ago
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    but i dont understand answer is 871

  13. King
    • 3 years ago
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    oh sry wait its by what number less than 2must be multiplied with 43521.....

  14. King
    • 3 years ago
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    i by mistake frgt to mention 43521....:/

  15. Ishaan94
    • 3 years ago
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    Oh

  16. King
    • 3 years ago
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    so?

  17. Ishaan94
    • 3 years ago
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    Let x be the number, (435*100,000 + 521)*x = adasd...fsh791 So, last digit of x must be 1. The answer is clearly 871, but I did this problem with logic and it's really tough to explain logic unless your communication skills are really impressive. So... I am gonna tag @FoolForMath and @Mr.Math to see if they know some trick or the method you mentioned above.

  18. Ishaan94
    • 3 years ago
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    btw basic multiplication is what I used.

  19. King
    • 3 years ago
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    its 43521

  20. King
    • 3 years ago
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    not 43500521

  21. Ishaan94
    • 3 years ago
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    (435*1000 + 521)*x = adasd...fsh791

  22. Ishaan94
    • 3 years ago
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    My bad

  23. King
    • 3 years ago
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    its 43*1000 +521 or 435*100+21 rite?

  24. King
    • 3 years ago
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    435*1000 + 521)=435521

  25. Ishaan94
    • 3 years ago
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    yeah, again my bad :/

  26. King
    • 3 years ago
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    oh and u can use any method......

  27. Ishaan94
    • 3 years ago
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    but it doesn't matter, just get the 521 separately and then multiply it my x (the assumed number).|dw:1332944499486:dw|

  28. Ishaan94
    • 3 years ago
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    by* not my ...and sorry for the bad handwriting.

  29. FoolForMath
    • 3 years ago
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    871 is the answer, if you know the one line multiplication then this problem is a 10 seconder ;)

  30. King
    • 3 years ago
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    @Ishaan94 what hav u done in the diagram can u post a normal reply the diagram is very messy so i cant understand anythin..................

  31. Ishaan94
    • 3 years ago
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    http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG I already told you, it's hard to explain. I don't wanna word it out.

  32. Aadarsh
    • 3 years ago
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    @King , see my answer below. Hope u understand.

  33. Aadarsh
    • 3 years ago
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    Please check the attached document. Hope u r clear now.

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  34. King
    • 3 years ago
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    Thnx @Aadarsh!!

  35. Aadarsh
    • 3 years ago
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    Most welcome.

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