The velocity of a particle ts after it starts from rest is vm/s,where v=1.25t-0.05t^2.Find
i)the initial accelaration of the partcle
ii)the displacement of the partcle from its staring point at the instant when its accelaration is 0.05m/s^2

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acceleration = (v-u) /t
= [(1.25t - 0.05t^2) -0] / t
= t(1.25 - 0.05t) /t
= 1.25 - 0.05t ms^-2

ok

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