anonymous
  • anonymous
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Physics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
?
anonymous
  • anonymous
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anonymous
  • anonymous
question2

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anonymous
  • anonymous
first draw the free body diagram of ring showing all the forces acting on it
anonymous
  • anonymous
|dw:1332946827188:dw|
anonymous
  • anonymous
like that?
anonymous
  • anonymous
wat abt that 5N force? which component acts in the upward direction to oppose weight mg?
anonymous
  • anonymous
5cos30 =4.33N oH OK NOW THE FRICTIONAL FORCE =6.0-4.33=1.67N
anonymous
  • anonymous
yes but how? dont u want to know why?
anonymous
  • anonymous
Yes why
anonymous
  • anonymous
add that 5cos@ component in ur free body diagram
anonymous
  • anonymous
|dw:1332947367531:dw|
anonymous
  • anonymous
yes so altogether? how does it look on the body?
anonymous
  • anonymous
its |dw:1332947814228:dw|clear on the body
anonymous
  • anonymous
thats it u did it! dont worry about horizontal component of 5N(5sin30) as the bar will balance this force by its normal force(anyway it is rigid) so for the next part wat is frictional force=? in terms of co-eff of friction
anonymous
  • anonymous
f=mewR
anonymous
  • anonymous
f=cefficient of friction xR
anonymous
  • anonymous
u can find it?
anonymous
  • anonymous
1.67=cofficientx4.33 coefficient=1.67/4.33 =0.385
anonymous
  • anonymous
yes u deserve a medal....
anonymous
  • anonymous
u have the anser for the 2nd question,i have a 2nd thought on it
anonymous
  • anonymous
but sadly the marking scheme says that R=5 SIN30 =2.5 And the constant of friction is 0.668
anonymous
  • anonymous
i thought so!
anonymous
  • anonymous
wat is normal reacftion exerted by a body?
anonymous
  • anonymous
normal recation=mg i think
anonymous
  • anonymous
no wat is it actually the concept /meaning behind it? normal=====perpendicular have u heard abt it?
anonymous
  • anonymous
normal reaction is at right angles with surfaces
anonymous
  • anonymous
right angle wit the surfaces in contact theree can be a normal force from a body in contact with another surface/body perpendicular to the plane in which both lie check this for any other place where u used normal reaction so here the only force normal to the plane of ring and touching tube is only 5sin30 get it?
anonymous
  • anonymous
wow awesome :)
anonymous
  • anonymous
:)
anonymous
  • anonymous
thanks boss this was a clever question it needs a free and relaxed mind,otherwise if not so and if it was exam exam it was gonna give me a nice time
anonymous
  • anonymous
np anytime all u have to do is get wat u learn deep in your mind in a clear way:) thank u for helping me figure out the normal reaction part(it was tld to me long ago by my sis)
anonymous
  • anonymous
ok what are about if the surface was smooth would that change anything?
anonymous
  • anonymous
then will the upward force 5cos30 force balance the weight mg? will it be enough to keep it in equilibrium?
anonymous
  • anonymous
no it wouldnt and it wouldnt be enough to balance the equilibrum
anonymous
  • anonymous
so? it will fall down with a force mg-5co30
anonymous
  • anonymous
therefore force of friction will be that right
anonymous
  • anonymous
smooth=-=====no friction
anonymous
  • anonymous
i have to go now post ur question here and send me the link bye!
anonymous
  • anonymous
ok thank u boss

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