If 62.7 g N2 react with 23.8 g H2 according to the reaction below, how many grams of ammonia (NH3) can be produced, and how many grams of the excess reactant will be left over?
Unbalanced equation: N2 + H2 → NH3

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How many moles of N2 and H2 do you have?

62.7 g N2 * mol/28g = 2.24 mol
23.8 g H2 * mol/2g= 11.9 mol ?????

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