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Write an equation for the locus of points equidistant from the lines y=3-3x and y=3x-3 .

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first we need to find two point the same distance away from each equation
so the first point can the intersection of the two line s y=3-3x y=3x-3 y=y 3-3x=3x-3 6x=6 x=1 therefore y =0 (0,1) we just need one more point and then we make an equation for that line

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ok so whats the next step to get the last point @benice
ok so we could pick say y =6 for both lines y=3x-3 6=3x-3 3x=9 x=3 (3,6) y=3-3x 6=3-3x 3=-3x x=-1 (|dw:1332966561289:dw|-1,6)
so in my poor drawing we have two points on the lines... you need to find the midpoint of the line to get your second point
what is the formula to find the midpoint again @benice
(x1+x2)/2 , (y1+y2)/2
so do you multiply the amounts add subtract what ? @benice
|dw:1332967284309:dw| for example
so it would be (3+-1) /2 ,( 6+6) /2 ?
and that is ( 1,6 ) the final answerr ? @benice ?
and then what do you do after that to solve the problem ?
remeber we need to find an equation that equal distance from both lines so we decide we would get two points (0,1) (1,6) now with these two points equal distance from both the lines this means they are on the line we are looking for so ,... how do the equation of the line with two points?
sorry the points are (1,0) (1,6)
ok so now we have what we need to find the locus ? @benice
yes find that line equation and your done
ohh you see i didnt even know you responded back -__ - what is the formula for line equation ? @benice

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