anonymous
  • anonymous
Find the volume of the solid obtained by rotating the region under the curve y=1/(sqrt(x+1)) from 0 to 1 about the x-axis. I don't remember these volume questions too well so hopefully someone can clarify. radius = integral 1/(sqrt(x+1)) dx volume = 2pie(radius) ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
use the washer method
anonymous
  • anonymous
v=pie(radius)^2 ?
anonymous
  • anonymous
your using integrals right?

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anonymous
  • anonymous
yeah
anonymous
  • anonymous
okay, so this is gonna form a solid with like a hole inside it like a washer, so we can use this formula:|dw:1332975346163:dw|
anonymous
  • anonymous
What would be the g(x)? If none, it would be setup like this right? \[\pi \int\limits_{0}^{1} (1/(\sqrt(x+1))^2 dx\]
anonymous
  • anonymous
\[2\pi(\sqrt(2)-1) \] is the solution? text has the solution as \[\pi \ln2\]
anonymous
  • anonymous
Not sure if this website archives these, solved it.. I wasn't squaring it.
anonymous
  • anonymous
i've been there :)
anonymous
  • anonymous
Thanks for your help LagrangeSon678!

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