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trouble setting up the equations? solving them? or both?
trouble setting up
ok, we want to know how many hard cover books they bought, so let that be X
let the paperbacks be Y can you write an equation for the total number of books sold?
26 = 4x + 2y
yes... and that was the hard equation to get but we need one more, since there are two variables.... so how many books were sold and what were they?
8 books were sold and were hard covered
why were they all hard covered? where does it say that?
but if that were true, your other equation would be X = 8 and this problem would be solved... don't think that's right though
X is the number of hardbacks; Y is the number of paperbacks; so...
unfortunatly this is all the book gave me as a question, although i paraphrased
you are overthinking this.... you know how many books were sold, some paper, some hard, so the equation is
how do you calculate a total?
that is my problem. This is the problem word for word A library is having a book sale to raise money. Hardcover books cost $4 and paperback books cost $2 each. A person spends $26 for 8 books. How many hardcover books did she purchase?
number of hardbacks sold + number of softbacks sold = 8 right?
I really don't know
how many books did she buy?
yes... and some were hardbacks and some paperbacks
but we need to write that in terms of X and Y
the number of hardbacks + the number of paperbacks = total number of books
so 4x + 2y?
no... still overthinking it... X + Y = 8
we said X was the number of hardbacks and Y was the number of paperbacks and we were told that 8 books in total were sold so X + Y = 8 does that make sense?
now comes the harder part... which you already did
so is this a system of equations ?
((hardback price)(number of hardbacks) + (paperback price)(number of paperbacks) = total money spent
yes, two variables needs two equations to solve
just plug in the letters and numbers and you have both equations (this is the one you said way back up there somewhere)
got it ! thank you !