anonymous
  • anonymous
Given f(x)=x^2+1, determine f(1/x), x does not equal to 0. Why is it:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
well plug in 1/x to the function so thats (1/x)^2 + 1 that equals (1/x^2) + 1 x cannot equal zero because 1/0 is undefined
anonymous
  • anonymous
Why is the process: \[\left(\begin{matrix}1 \\ x ^{2}\end{matrix}\right) + \left(\begin{matrix}1\times x ^{2} \\ 1 \times x ^{2}\end{matrix}\right)\]
anonymous
  • anonymous
\[\left(\begin{matrix}1 \\ x ^{2}\end{matrix}\right) + \left(\begin{matrix}x ^{2} \\ x ^{2}\end{matrix}\right)\]

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anonymous
  • anonymous
answer: \[\left(\begin{matrix}1 + x ^{2} \\ x ^{?}\end{matrix}\right)\] Can someone explain to me why it's this process I should do?
anonymous
  • anonymous
x≠ 0 is just a condition to guarantee f(1/x) exist! You don't have to do anything.
anonymous
  • anonymous
that's what my teacher showed me but I'm having trouble understanding it.
anonymous
  • anonymous
x= 0 is not belong to domain of f(1/x) Since if x= 0 --> f(1/x ) = ∞ ( undefined)
anonymous
  • anonymous
ohh, okay.
anonymous
  • anonymous
That's the rule, just memorize it whenever you see fraction, domain is numerator must be≠ 0
anonymous
  • anonymous
alright, thank you!
anonymous
  • anonymous
:)
anonymous
  • anonymous
I mean *denominator* must be ≠ 0!
anonymous
  • anonymous
okay!

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