Consider the curve given by x^2+3y^2= 1 +3xy
show that dy/dx = 3y-2x / 6y-3x
ok so while i was doing this by hand I ended up with 3y-2x / 6y. I dont know what happened but that 3x on the bottom threw me off. O.o help?
Stacey Warren - Expert brainly.com
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do you have your work to get there?
@liizzyliizz Show us your work, so we know where you misunderstood!
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okey dokes I shall do that now.
|dw:1332986182859:dw| ok so i was looking at my work, and i have both of these things written down. I know somewhere I went wrong, and started doing something that doesn't make much sense, but I haven't been able to figure out what I am forgetting to do.
It does seem like your reaction to the "3xy"'s derivative was justified...
3xy is a product of two, what we could call 'functions.' We do have to use product rule on it.
Knowing where's you're wrong is the first step to be correct :)
dy/dx ( 3 x y ) = 3 y + 3 x dy/dx
yep. should work out using that 3y + 3x dy/dx. I think your process was correct, that was the only issue -- the derivative of 3xy. :)