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## l6harris 2 years ago the equation of motion for a particle in meters at time t seconds is s(t)=sin(pi(t)/6)+cos(pi(t)/6), 0 is less then/equal to t is less then or equal to 2. What is the acceleration at the instant the velocity is 0

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1. y2o2

$\huge s(t) = \sin({\pi t \over 6}) + \cos({\pi t \over 6})$ $\huge v(t) = {ds \over dt} = {\pi \over 6} \cos({\pi t \over 6}) - {\pi \over 6}\sin({\pi t \over 6})$ $\huge a(t) = {dv \over dt} = -({\pi \over 6 })^2 \sin({\pi t \over 6})-({\pi \over 6 })^2 \cos({\pi t \over 6})$ let v = 0 to get t then substitute with this t in the function of a

2. cinar

then t=3/2 a=-0.388m/s^2

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