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(x^2-25)(x^2-9)=0 x^2=25 or x^2=x = 5, -5, 3, -3 Smallest solution is -5
What's your first step
To factor the trinomial you posted.
How do you factor it?
I don't understand you question. Don't you see the factors I posted? That's how you factor it.
No, that's the result you get after factoring it, its factors. Show me how you came up with the two binomials
Do you know how to factor? Factor this: \[x^2-34x+225\]
Try to think of two numbers. Their product is 225 and their sum is -34
yes i know how to factor quadratic equations
Then factor the example I gave you and tell me what the factors are.
Fill in the blanks in both of those.
i dont see how they are the same though, one is cuartic and one is quadratic
You multiply two binomials in exactly the same way regardless of the terms of the binomial.
No difference. As long as the exponent is even.
just use substitution x^4-34x^2+225=0 let u=x^2 u^2-34u+225=0 (u-25)(u-9)=0 reverse the substitution: (x^2-25)(x^2-9)=0 and factor the difference of 2 squares
Ok. Dockworker wants to help you now. Good Bye.
Okay, thanks, that's better now.