anonymous
  • anonymous
What is the smallest solution of the equation x^4 - 34x^2 + 225 = 0?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Mertsj
  • Mertsj
(x^2-25)(x^2-9)=0 x^2=25 or x^2=x = 5, -5, 3, -3 Smallest solution is -5
anonymous
  • anonymous
What's your first step
Mertsj
  • Mertsj
To factor the trinomial you posted.

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anonymous
  • anonymous
How do you factor it?
Mertsj
  • Mertsj
I don't understand you question. Don't you see the factors I posted? That's how you factor it.
anonymous
  • anonymous
No, that's the result you get after factoring it, its factors. Show me how you came up with the two binomials
anonymous
  • anonymous
not sure
Mertsj
  • Mertsj
Do you know how to factor? Factor this: \[x^2-34x+225\]
Mertsj
  • Mertsj
Try to think of two numbers. Their product is 225 and their sum is -34
anonymous
  • anonymous
yes i know how to factor quadratic equations
Mertsj
  • Mertsj
Then factor the example I gave you and tell me what the factors are.
anonymous
  • anonymous
(x-25)(x-9)
Mertsj
  • Mertsj
|dw:1332986382278:dw|
Mertsj
  • Mertsj
Fill in the blanks in both of those.
anonymous
  • anonymous
i dont see how they are the same though, one is cuartic and one is quadratic
Mertsj
  • Mertsj
|dw:1332986555421:dw|
anonymous
  • anonymous
quartic*
Mertsj
  • Mertsj
You multiply two binomials in exactly the same way regardless of the terms of the binomial.
Mertsj
  • Mertsj
|dw:1332986643207:dw|
Mertsj
  • Mertsj
No difference. As long as the exponent is even.
anonymous
  • anonymous
just use substitution x^4-34x^2+225=0 let u=x^2 u^2-34u+225=0 (u-25)(u-9)=0 reverse the substitution: (x^2-25)(x^2-9)=0 and factor the difference of 2 squares
Mertsj
  • Mertsj
Ok. Dockworker wants to help you now. Good Bye.
anonymous
  • anonymous
Okay, thanks, that's better now.

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