anonymous
  • anonymous
an 18ft ladder leans against a wall. the bottom of the ladder is 5ft from the wall at t=0 and slides away at a rate of 2 ft/sec. Find the velocity at t=3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
unless I'm missing something, the velocity is 2ft/sec and it's constant, isn't it?
anonymous
  • anonymous
i have to use derivatives it is a related rates problem
anonymous
  • anonymous
Do you have any sample at all?

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anonymous
  • anonymous
what do you mean sample?
anonymous
  • anonymous
z² = x² + y² ->y dy/dt = - x dx/dt => dy/dt = - x dx/dt / y At t = 3 => x = 5 ft + 3 * 2 = 11 ft => y = √ (18² - 11²) = 14.25 ft Thus dy/dt = - 11 * 2 / 14.25 = -1.54 ft/sec
anonymous
  • anonymous
Your lecture or some homework?
anonymous
  • anonymous
That's the best I can visualize! It'd be perfect if I know what are you learning!
anonymous
  • anonymous
oh yea i had an example from lecture.. but i couldn't figure out from my notes where one of the numbers came from
anonymous
  • anonymous
how can the answer be negative?
anonymous
  • anonymous
Could you attach, so I can make sure my solution is 100% correct!
anonymous
  • anonymous
im not sure how to attach but it is correct thank you
anonymous
  • anonymous
Negative is the direction, which the laddter is sliding down!
anonymous
  • anonymous
How do you know it's correct :)
anonymous
  • anonymous
online homework
anonymous
  • anonymous
So you enter the result already?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Yeehh, great! I hate to give sloppy answer!
anonymous
  • anonymous
The online homework is very tricky, sometimes if you're miss the sign or decimal point, your answer is rejected!

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