anonymous
  • anonymous
need help constructing truth tables for conditional statements
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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KingGeorge
  • KingGeorge
Is there a particular aspect of truth tables you're having trouble with?
anonymous
  • anonymous
construct a truth table for (q ^ p) ---> ~p yes, not sure how to treat the conditional outside of the parentheses
KingGeorge
  • KingGeorge
First, draw two columns. One with possible values of the truth of P, and the other with Q so that all possible combinations are made.|dw:1332988660195:dw|

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KingGeorge
  • KingGeorge
Then create another column column containing the truth values of (p ^ q) |dw:1332988845028:dw|
anonymous
  • anonymous
I know how to setup the chart, but not sure after that
anonymous
  • anonymous
i have across the top : q | p | (q | ^ | p) | --> | ~p
KingGeorge
  • KingGeorge
Now we have to treat that conditional you were talking about. Instead of thinking of (p ^ q) as two hypotheses with a conditional, think of as another hypothesis. So let r = (p ^ q).
anonymous
  • anonymous
my teacher gave an example, but never one with the conditional outside of the parentheses that's my confusion.
KingGeorge
  • KingGeorge
You already have the truth values for r, so now make two more columns; a column for ~p, and the final one.|dw:1332989078420:dw|
KingGeorge
  • KingGeorge
And the last column will be r-->~p|dw:1332989176469:dw|
KingGeorge
  • KingGeorge
If the conditional is outside the parentheses, you have to do what's inside first, and use that as a new hypothesis.
anonymous
  • anonymous
awesome. thanks. so the parentheses were throwing me off, but they are simply q and p
anonymous
  • anonymous
q AND p
anonymous
  • anonymous
thank you.
KingGeorge
  • KingGeorge
(q ^ p) is the same thing as (p ^ q). If you see parentheses and you have to do truth tables for them in the future, pretend it's a weird version of arithmetic, and you have to show every single step very clearly. You're welcome. :)
anonymous
  • anonymous
i'm posting another question! :)

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