anonymous
  • anonymous
The perimeter of a rectangular concrete slab is 114 feet and its area is 702 square feet. Find the dimensions of the rectangle. a. Using l for the length of the rectangle, write an expression for the width of the rectangle in terms of l. (Hint: Solve the formula for w.) Show your work. b. Write a quadratic equation using l, the expression you found in part (a), and the area of the slab. c. Solve the quadratic equation. Use the two solutions to find the dimensions of the rectangle. PLz, Plz show work if you can. Thanks so much
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
deja vu we have 2 equations, 1 for perimeter and 1 for area, both in terms of l&w P=2L+2W A=LW We know P and A 2L+2W=114 LW=702 Let's solve for W in terms of L in the perimeter equation: 2L+2W=114 L+W=57 W=57-L Now let's substitute this value into the area equation: LW=702 L(57-L)=702 57L-L^2=702 L^2-57L+702=0 factor this into: (L-18)(L-39)=0 L=18, 39 Now we have the possible lengths: 18 and 39 If the length is 39, the width is 702/39=18 because LW=702 39W=702 W=18 If the length is 18, the width is 702/18=39 So the dimensions of the rectangle are 39 ft X 18 ft You can check this by plugging these values back into the perimeter and area equations: LW=702 (18)(39)=702? true, this works 2(18)+2(39)=114? 36+78=114? 114=114? true
anonymous
  • anonymous
thanks, so much
anonymous
  • anonymous
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.