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This is so easy. What is y when x=1? What is y when x=2? when x=3? And so on.
Nm, didn't see that that's the derivative. One sec.
It looks like it would be simple - but where is the original function
Okay, so we start at f(0) = 3. Well at f'(1), the slope is -4. So for finding f(1), we can start at f(0)=3. Then go down 4 on the y-axis and then go right 1 on the x-axis. Not sure how correct this is, let's see what others have to say.
Oh duh, ya you're on the right track brine
Im still confused.
Ugh, me too.
haha tricky biz
So I think f(1)=-1. Then go down 4 and over 1 to the right again. Then you'll have f(2)= -5
hmm let me look at it
That could be it. I just have to be certain cuz it gives me like one or two chances
I see. Does your book have any examples similar to this? I know how much of a pain these online assignments can be.
No hahah it does but it so doesnt help at all
Okay if you can give me a sec, I found a similar HW problem from Rogawski's book and I can get you a soln from cramster. Hopefully, it'll help a little.
thank you so much
crap, I keep running into a brick wall. When do you have to turn this in?
Im tryingt o get it done tonight
Do you think ur original idea is right
Now I'm thinking that you should start 0,3 and the function curves down until it gets to x=1. Seems to me like f(1)=2. But in all honesty, I would repost this question. Then go back and deletes this old post. Try to ask people in the chatbox as well.
This is SUCH a visual thing and I can't believe they would ask something like this. I mean, you can understand the concept perfectly but still get this one wrong. :-(
I'm sorry I can't give you a straight answer, I feel bad.
Don't feel bad!
After you repost this question, go back and delete the old post.