I need help with calculus.
i need to find the volume of the solid generated by revolving region bounded by the graphs of the equations about the x-axis.
y= 1/(square root of x+1) , y=0 x=0 and x=3
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
i'm not sure what the radius would be.
you have to graph it to find the radius, usually it is called "x" and then we call height the y output values which is the long equation y=_____________ you gave. from there we have and area equation. then we know that the volume is just the integral of the area function from some a to b (that you set by looking at the graph)
would the interval be from 0 - 1 or 0-3? if its revolving around "x"