A 13kg box slides 4.0m down the frictionless ramp shown in the figure , then collides with a spring whose spring constant is 170 N/m.
Figure : http://i.imgur.com/0M7us.png
What is the maximum compression of the spring?
At what compression of the spring does the box have its maximum speed?
I'm stuck on the first question.
I thought I use mgh = (1/2)kx^2?
so, (13kg)(9.8m/s^2)(4sin(30)) = (1/2)(170N/m)x^2.
x = √(2mgh / k) = 1.7m?
But it's telling me this is wrong
Any help please?

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I don't understand, I have to find v first?

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