• anonymous
A 13kg box slides 4.0m down the frictionless ramp shown in the figure , then collides with a spring whose spring constant is 170 N/m. Figure : http://i.imgur.com/0M7us.png What is the maximum compression of the spring? At what compression of the spring does the box have its maximum speed? I'm stuck on the first question. I thought I use mgh = (1/2)kx^2? so, (13kg)(9.8m/s^2)(4sin(30)) = (1/2)(170N/m)x^2. x = √(2mgh / k) = 1.7m? But it's telling me this is wrong Any help please?
Physics
• Stacey Warren - Expert brainly.com
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SOLVED
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